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2 years ago

What would be the linear equation for (0,2) and (4,-4)

Mathematics

1 answer:

GalinKa [24]2 years ago

6 0

Answer:your mom

Step-by-step explanation:

srry had to do it

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Does anyone know how to do this?

sineoko [7]

Answer:

$\boxed{\tt x=\sqrt{85} }$

Step-by-step explanation:

When making a right triangle with 2 points, the distance is the hypotenuse which can be represent as "x"

To find the distance we can use the Pythagorean theorem.

$\boxed{{\tt a^2+b^2=c^2}}$

→ $\tt a=9$

→ $\tt b=2$

→ $\tt c=x$

Let's Plug in the side lengths:

$\tt 9^2+2^2=x^2$

Evaluate 9²= 81 and 2²= 4:

$\tt 81+4=x^2$

Now, add 81+4= 85

$\tt 85=x^2$

Take the square root of both sides:

$\tt x=\sqrt{85}$

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5 0

3 years ago

8. Simplify and solve this equation: 4m + 9 + 5m – 12 = 42. A. m = 5 B. m = –5 C. m = 4 D. m = -4

STatiana [176]

4m+9+5m-12=42 9m-3=42 Divide bothsides by 9. 9m/9 -3/9=-0.3=-4 m=-4

4 0

3 years ago

Read 2 more answers

HELP MEEE OMGGGG JESSUS AMENNN

irina1246 [14]

Answer:

Answers in the pics

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

8 0

3 years ago

Steve drove at a constant rate to the beach for a vacation. In the equation below, t is the time in hours it took Steve to drive

My name is Ann [436]

310/62= hours which equals 5! hope this helped a bit.

5 0

3 years ago

Read 2 more answers

Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance

lana66690 [7]

Answer:

Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.

Let p = population proportion of users who develop nausea

So, Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Here, null hypothesis states that 20% of users develop nausea.

And alternate hypothesis states that more than 20% of users develop nausea.

The test statistics that would be used here is One-sample z proportion test statistics.

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of users who develop nausea in a sample of 241 subjects = $\frac{54}{241}$

n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0

4 years ago