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n200080 [17]
3 years ago
15

Which of the following could be a possible internal stimuli that would cause a group of elephants to

Mathematics
1 answer:
xenn [34]3 years ago
8 0

Step-by-step explanation:

huqrhqrthwtjwtjqrbqrhqrnstntwtnatmwtnafnafnFnFnFnfCnV V V V zv.agmsgmgsgmstmsgmafnafnadnarnafnarnadenafnVnvCnVmvC FgnzvvmGnGnfF

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Aaron has $4,500 saved to pay for an ATV that costs $7,500.
Komok [63]

Answer:

i think its 0.9994225

Step-by-step explanation:

just subtract the 8.75136.24 bye 7.75193. and there you go.

6 0
3 years ago
Someone help pleaseee
gregori [183]

Answer:

the answer is 1/2 which loos like "D"

Step-by-step explanation:

the top ends up being x ^-8 and the denominator is x^-7

which is x^&/x^8 = 1/x = 1/2

4 0
2 years ago
Find the quotient and remainder when 5x4-3x2+2x-4 is divided by x-3​
blagie [28]

Step-by-step explanation:

5x4-3x2+2x-4/x-3

=2x+5×4-3×2-4/x-3

=2x+32/x-3

3 0
2 years ago
in a triple batch of spice mix, there are 15 teaspoons of salt and 6 teaspoons of garlic powder. how much salt is used with 8 te
NISA [10]

Answer: I would say 24 manybe...I might be wrong

Step-by-step explanation:

6 0
2 years ago
If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
goldenfox [79]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

3 0
3 years ago
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