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Gala2k [10]
3 years ago
7

HELP ME AGAIN I MIGHT PASS

Mathematics
2 answers:
zhenek [66]3 years ago
6 0

Answer:

70

Step-by-step explanation:

The angles <FEB and <AEG are vertical angles. This means they have the same measurement. To find <FEB add the two angles <FED and <DEB together. This equals 70; therefore, x must also be equal to 70 degrees.

trapecia [35]3 years ago
4 0

Answer:

x=70

Step-by-step explanation:

it's 70 because 50 and 20 is proportional to x

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Bill is 4 years older than Harris, who is 5 years old. How old is Bill? Plot Bill’s age on the number line.
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Bill is 9 years old

Step-by-step explanation:

Bill is 4 years older than 5 year old Harris. 5+4 is 9 so plot Bill on the number line as 9.

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Question 5 of 10<br> Which of the following functions best describes this graph?
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4 years ago
What is the least common denominator of 1/2 5/6
Liula [17]

Answer:

Multiples of 4:4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, …

Multiples of 6:6, 12, 18, 24, 30, 36, 42, 48, 54, 60, …

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2 years ago
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A gasoline tank for a certain car is designed to hold 15 gallons of gas. Suppose that the actual capacity of a randomly selected
marta [7]

Answer:

Tanks of 15.3081 gallons and larger are considered too large.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 15, \sigma = 0.15

How large does a tank have to be to be considered too large

largest 2%, so at least the 98th percentile.

The 98th percentile is X when Z = 0.98. So it is X when Z = 2.054.

Z = \frac{X - \mu}{\sigma}

2.054 = \frac{X - 15}{0.15}

X - 15 = 2.054*0.15

X = 15.3081

Tanks of 15.3081 gallons and larger are considered too large.

8 0
3 years ago
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