9514 1404 393
Answer:
∠4 = 45°
Step-by-step explanation:
Angles 1, 2, and 4 are all congruent.
∠4 = ∠2
x +30 = 2x +15
15 = x . . . . . . . . . . . . . subtract x+15
x + 30 = 45 = ∠4
Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.
This rule has the form
h(t) = h + v t + (1/2)a*t^2
o o
To adapt this rule to this particular question replace h with 0, as the
o
upward path of the object begins at 0 ft. Replace v with +15 ft/sec.
o
Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.
Then we have the following, with the label F(t):
F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or
F(t) = 15t - 16.1t^2. Thus, Choice D is correct.
Please note: To avoid confusion, please use " ^ " to denote exponentiation:
F(t) = -16t^2 + 15t
Answer:
Y=5x
Step-by-step explanation:
The first the options aren’t even whole numbers
