Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
86
Step-by-step explanation:
21 <u>3</u>6
<em>5</em>2 <em>4</em>0
<u>3</u>2 <em><u>86</u></em>
<u>3</u>3 <u>3</u>8
28 <u>3</u>4
<u>3</u>0 <em>1</em>9
Step-by-step explanation:
SO, OT is parallel to the vector a+2b
It'd be A since dividing on a negative coefficient results flipping the sign of the inequality and results in a different impact
Answer:
D
Step-by-step explanation:
Area of triangle= ½ ×base ×height
Since the length of the base and the height of the triangle is equivalent to the length of a side of the square, s,
area of triangle
= ½ ×s ×s
= ½s²
Given that the area of the triangle is 12.5 units²,
½s²= 12.5
Multiply both sides by 2:
s²= 12.5(2)
s²= 25
Square root both sides:
s= 5 units
(reject negative value since s > 0)
