Is there any other information given on this?
The product (multiplication) of 5 and m squared (²) increased (addition) by the sum (addition) of the square (²) of m and 5.
(5m²) + (m² + 5)
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer:
The length of AB = 97/3 units
Step-by-step explanation:
We know that a rhombus is a quadrilateral whose four sides all have the same length.
Thus, the equation becomes
7x+2 = 4x+15
7x-4x = 15-2
3x = 13
x = 13/3
So, the length of CD = 7x+2 = 7(13/3)+2
= 91/3 + 2
= 97/3
And, the length of BC = 4x+15 = 4(13/3) + 15
= 97/3
- We already know that a rhombus is a quadrilateral whose four sides all have the same length.
Thus, the length of AB = 97/3 units
