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navik [9.2K]
4 years ago
6

PLEASE HELP What is the equation of the line shown?

Mathematics
1 answer:
Ivenika [448]4 years ago
8 0

So, let's start off with explaining what these different questions mean;

y = |x + c| Shifts the graph c units left.

y = |x - c| Shifts the graph c units right.

y = |x| + c Shifts the graph c units up.

y = |x| - c Shifts the graph c units down.

(0,0) Is the starting point on any graph like this. So, determine the answer by going through the list of answers.

I believe the answer is y = 2x.

I would like to know if I am wrong so contact me!!

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Is ax^2 the same as 2ax
Korolek [52]
No there's a difference between it, I know what it was on the tip of my tongue but I forgot it <span />
6 0
3 years ago
Read 2 more answers
Please help i will give brainliest!!!
Shalnov [3]
D) (-2,3)

-2 is the x-value
3 is the y-value

If you look at the graph on the x-axis (horizontal line) the numbers are increasing and decreasing by 1.
Since the point of intersection (big blue dot) is on the left side of 0, it falls directly at the -2 mark
As for the y-axis (vertical lines) the numbers also increase and decrease by 1. The point of intersection falls above 0 at +3

Therefore your point of intersection is (-2,3)
8 0
3 years ago
Please help me i really need this grade !
Goshia [24]

Answer:

C. 8

Step-by-step explanation:

still using the equation a^2 = b^2 = c^2

8 0
3 years ago
Find AM in the parallelogram if PN =15 and AO = 6. The diagram is not to scale.
valentinak56 [21]

Answer:

6

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

The diagonals are PN and MO. The point A divides PN into 2 equal segments as well as MO into 2 equal segments.

Since AO = 6, MA should also be equal. Hence, MA (or AM) = 6.

The correct answer is AM = 6

7 0
3 years ago
What is the solution to the equation? (-9x+5)^1/2=(3+4x)1/2
Phoenix [80]
<span>x in (-oo:+oo)

((5-9*x)^1)/2 = ((4*x+3)^1)/2 // - ((4*x+3)^1)/2

((5-9*x)^1)/2-(((4*x+3)^1)/2) = 0

(5-9*x)/2-((4*x+3)/2) = 0

(5-9*x)/2+(-1*(4*x+3))/2 = 0

5-1*(4*x+3)-9*x = 0

2-13*x = 0

(2-13*x)/2 = 0

(2-13*x)/2 = 0 // * 2

2-13*x = 0

2-13*x = 0 // - 2

-13*x = -2 // : -13

x = -2/(-13)

x = 2/13

x = 2/13</span>
4 0
4 years ago
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