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irinina [24]
3 years ago
13

Will give any wanted points!! help quick!!

Mathematics
1 answer:
gayaneshka [121]3 years ago
4 0

Here , the ratio <em><u>UV:</u></em><em><u>VW</u></em> and <em><u>UT:TS</u></em> will be in proportion , so ;

{:\implies \quad \sf \dfrac{UV}{VW}=\dfrac{UT}{TS}}

Putting the given values ;

{:\implies \quad \sf \dfrac{18}{36}=\dfrac{UT}{24}}

{:\implies \quad \sf UT=\dfrac{1}{2}\times 24}

{:\implies \quad \bf \therefore \quad \underline{\underline{UT=12 \:\: units}}}

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PLEASE HELP ASAP !! (Picture included)
slega [8]

This is the question that's gonna put me over the top and make me a Brainly Genius. Of course working for free doing middle school math homework doesn't really sound like a genius, but I'm doing it anyway.

This one is the Pythagorean Theorem of course:

(x+3)^2 + (x+4)^2 = (x+10)^2

x^2 + 6x + 9 + x^2 + 8x + 16 = x^2 + 20 x + 100

x^2  - 6x - 75 = 0

The Shakespeare Quadratic Formula (2b or -2b) is a little shortcut for the quadratic formula when the middle term is even.

x^2-2bx+c \textrm{ has zeros } x=b\pm \sqrt{b^2-c}

So we get

x = 3 \pm \sqrt{3^2 -(-75)} = 3 \pm \sqrt{84} = 3 \pm 2 \sqrt{21}

The minus root is less than -6 giving negative sides, so we reject it and conclude

x = 3 +  2 \sqrt{21}

Choice C

When I hit Add I officially become a Genius. Maybe I should retire.


8 0
4 years ago
A penny weighs 2.5 grams while a dime weighs about 2.27 grams . How much does a penny and two dimes weigh ?
andreev551 [17]

Answer: 7.04 grams

Step-by-step explanation: 2.27x2=4.54 + 2.5 = 7.04 g.

5 0
3 years ago
Read 2 more answers
What are the values of the trigonometric ratios for this triangle?
nika2105 [10]

Answer:

sin = o/h = 5/13

cos = a/h = 12/13

tan = o/a = 5/12

o - opposite

a- adjacent

h - hypotenuse

6 0
2 years ago
What is the equation of the line, in general form, that passes through the point (1, 1) and has a y-intercept of 2. x - y + 2 =
belka [17]
Slope = (2-1)/(0-1) = -1

equation
y = -x +2

general form
x + y  - 2 = 0

answer

x + y  - 2 = 0
3 0
4 years ago
Read 2 more answers
How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and
omeli [17]

Step-by-step explanation:

x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\     (given)

Let us consider :

x_{1} = t_{1} + 1

x_{2} = t_{2}

x_{3} = t_{3}

x_{4}  = t_{4}

x_{5} = t_{5}

Now, by substituting the above considerations in the above equation, we get:

t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\

t_{1}  + t_{2} + t_{3} + t_{4} + t_{5} = 20\\

where,

t_{i} \geq 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = _{r}^{n + r}\textrm{C}

                                                      = _{4}^{24}\textrm{C}

                                                      = 10626

Answer :

no. of solutions for the eqn 10626

4 0
4 years ago
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