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Andrei [34K]
3 years ago
13

What is the image point of (1,-1)(1,−1) after a translation left 4 units and down 5 units?

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

The new point would be (-3,-6)

Step-by-step explanation:

To solve this it is nice to graph the first point at (1,-1). Then move the point left 4 units, making x -3. and then 5 units down, which would make y -6.

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The radius of a cylindrical vessel is 7 cm and height is 1400 m . Find the cost of painting its inner curved surface area at the
Olegator [25]

Answer:

Cost = 616000 DHS per square centimetre.

Step-by-step explanation:

curved surface of a cylinder = 2\pirh

r = 7 cm

h = 1400 m = 140000 cm

The outer curved surface area of the cylinder = inner curved surface area of the cylinder

The inner curved surface of the cylinder = 2\pirh

                                      = 2 x \frac{22}{7} x 7 x 140000

                                      = 2 x 22 x 1 x 140000

                                      = 6160000

The inner curved surface of the cylinder is 6160000 square centimetre.

But, the cost of painting is at the rate of 10 DHS per square centimetre.

The inner curved surface of the cylinder = 6.16 x 10^{6} square centimetre.

cost of painting the inner curved surface area = \frac{6.16*10^{6} }{10}

                                                                       = 616000 DHS per square centimetre

The cost of painting the inner surface is 616000 DHS per square centimetre.

6 0
3 years ago
How do I find the radius of a circle
katovenus [111]

Answer:

Step-by-step explanation:

Just remember to divide the diameter by two to get the radius. If you were asked to find the radius instead of the diameter, you would simply divide 7 feet by 2 because the radius is one-half the measure of the diameter. The radius of the circle is 3.5 feet. You can also use the circumference and radius equation.

6 0
3 years ago
Read 2 more answers
Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a
cluponka [151]

Answer:

B. Train B  

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

\text{Distance}=\text{Speed*Time}  

\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}

\text{Distance traveled by train A}=90\times 3{\text{ miles}

\text{Distance traveled by train A}=270{\text{ miles}

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}

\text{Distance traveled by train B}=70\times 5 \text{ miles}

\text{Distance traveled by train B}=350\text{ miles}  

Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

5 0
3 years ago
What is the factored form of this expression?
kirill [66]

Answer:

= (3t+2)(3t-2)(3t-4)

Step-by-step explanation:

Given the expression 27t^3 - 36t^2 - 12t + 16

On factoring:

(27t^3 - 36t^2) - (12t + 16)

= 9t²(3t-4)-4(3t-4)

= (9t²-4)(3t-4)

factoring 9t²-4

9t²-4 = (3t)² - 2²

From different of two square, a²-b² = (a+b)(a-b)

Hence (3t)² - 2² = (3t+2)(3t-2)

= (9t²-4)(3t-4)

= (3t+2)(3t-2)(3t-4)

Hence the factored form of the expression is (3t+2)(3t-2)(3t-4)

6 0
3 years ago
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 50.7 d
Svet_ta [14]

Answer: The mean of the frequency distribution is 51.7°.

The computed mean 51.7° is greater than the actual mean 50.7° .

Step-by-step explanation:

The given table :

  Low Temperature ​(°​F)      Frequency     Mid -value  

      Class interval                  f                        x                  fx

          40-44                           2                     42.5               85

          45-49                           7                     47.5               95                      

          50-54                          9                     52.5               105

           55-59                         5                     57.5                115

           60-64                          1                      62.5               25

\text{Now, Mean}=\dfrac{\sum fx}{\sum f}\\\\=\dfrac{85+332.5+472.5+287.5+62.5}{24}\\\\=\dfrac{1240}{24}=51.6666666667\approx51.7

The computed mean 51.7° is greater than the actual mean 50.7° .

5 0
3 years ago
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