Answer:
Yes, 3(x+1)(x+7)-(2x+5)² is never positive
Step-by-step explanation:
So....
3(x+1)(x+7)-(2x+5)(2x+5)
=3(x²+8x+7)-(4x²+20x+25)
=3x²+24x+21-4x²-20x-25
=-x²+4x-4
The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
<h3>How to determine the sum of the notation?</h3>
The sum notation is given as:
∞Σn=1 2(1/5)^n-1
The above notation is a geometric sequence with the following parameters
- Initial value, a = 2
- Common ratio, r = 1/5
The sum is then calculated as
S = a/(1 - r)
The equation becomes
S = 2/(1 - 1/5)
Evaluate the difference
S = 2/(4/5)
Express the equation as products
S = 2 * 5/4
Solve the expression
S= 5/2
Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
Read more about sum notation at
brainly.com/question/542712
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first invert fraction of the slope from 4/1 to 1/4 and switch sign. then figure out the y-intercept
the algebraic approach would work like this:
-4x + 10 = 1/4x + b
plug in what you got, here: the intersection information
-4*(4) + 10 = 1/4*(4) + b
-16 + 10 = 1 + b
-6 = 1 + b
-7 = b
G(f(x))= (7x+8)^4
g(f(x))= (7(0)+8)^4
=(0+8)^4
=8^4
=8•8•8•8
=4,096
