Answer:
The value of x is 4
Step-by-step explanation:
In a right triangle, if a segment is drawn from the right angle ⊥ to the hypotenuse like the given figure, then
∵ The length of one side of the right triangle = (x + 2)
∵ The length of the hypotenuse = x + 5
∴ (x + 2)² = x (x + 5)
∵ (x + 2)² = (x + 2)(x + 2)
∴ (x + 2)(x + 2) = x(x + 5)
→ Simplify the two sides
∵ (x)(x) + (x)(2) + (2)(x) + (2)(2) = (x)(x) + (x)(5)
∴ x² + 2x + 2x + 4 = x² + 5x
→ Add the like terms in the left side
∴ x² + 4x + 4 = x² + 5x
→ Subtract x² from both sides
∵ x² - x² + 4x + 4 = x² - x² + 5x
∴ 4x + 4 = 5x
→ Subtract 4x from both sides
∴ 4x - 4x + 4 = 5x - 4x
∴ 4 = x
∴ The value of x is 4
Answer: 
Have attached the picture for explanation...
Answer:
the answer is c because it can be either greatly increased or decreased
Complete Question
A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?
Answer:
The value required is
Step-by-step explanation:
From the question we are told that
The upper specification is 
The lower specification is
The sample mean is
The standard deviation is 
Generally the capability index in mathematically represented as
![Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7BUSL%20-%20%20%5Cmu%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%20%2C%20%20%5Cfrac%7B%5Cmu%20-%20LSL%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%5D)
Now what min means is that the value of CPk is the minimum between the value is the bracket
substituting value given in the question
![Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7B1.68%20-%20%201.6%20%7D%7B%203%20%2A%20%200.03%20%7D%20%20%2C%20%20%5Cfrac%7B1.60%20-%20%201.52%20%7D%7B%203%20%2A%20%200.03%7D%20%5D)
=> ![Cpk = min[ 0.88 , 0.88 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%200.88%20%2C%200.88%20%20%5D)
So

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2
Now let assuming that

So

=> 
=> 
So

=> 
Hence
![Cpk = min[ 2, 2 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%202%2C%202%20%5D)
So

So
is the value of standard deviation required
2 is the correct answer....gitty up