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Natasha_Volkova [10]
3 years ago
6

Prove that 3(x+1)(x+7)-2x+5)^2 is never positive

Mathematics
1 answer:
lisov135 [29]3 years ago
5 0

Answer:

Yes, 3(x+1)(x+7)-(2x+5)² is never positive

Step-by-step explanation:

So....

3(x+1)(x+7)-(2x+5)(2x+5)

=3(x²+8x+7)-(4x²+20x+25)

=3x²+24x+21-4x²-20x-25

=-x²+4x-4

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Probability helps us to know the chances of an event occurring. There are six possible outcomes.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}

A.) The outcomes that are possible from the first spinner is 1, 2, and 3, while the outcomes possible from the second spinner are 2, Red and blue.

All the possible outcomes from this two spinner are,

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(B,1), (B,2), (B,3)(B,4), (A,1), (A,2), (A,3), and (A,4).

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Step-by-step explanation:

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What is 481 divided by 8?Is it 60 with a remainder of 1 ?
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An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
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Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that n = 48

The probability that any integrated circuit is defective is 0.01.

This means that p = 0.01

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

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0.6173 = 61.73% probability that the product operates.

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