1) X=159
2) BCD=103
3) DCH=89
im pretty sure
Answer:
value of x = 8
Step-by-step explanation:
if the given lines are parallel, then the shown pair of angles are corresponding angles,
and we know that the the pair of corresponding angles are equal so,
=》16x - 8 = 120
=》16x = 128
=》x = 128 ÷ 16
=》x = 8
Y = kx
when y= 12, x=3
12 = 3k
k = 12/3
k = 4
y = 4x
when x= 15
y = 4(15)
y = 60
(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
Answer:
cool
Step-by-step explanation:
2v + 7 = 3
- 7 - 7
2v = - 4
v = - 2
