According to the calculations made, 410 gumballs will be needed to fill the box.
Since you are trying to figure out how many gumballs you need to fill a 7.3 x 5.0 x 9.4 rectangular box for Halloween, and each gumball has a radius of 1/2 in, if the packing density for spheres is 5/8 of the volume will be filled with gumballs while the rest will be air how many gumballs will be needed, to determine this amount the following calculation must be performed:
- (Volume of box x 5/8) / volume of gumballs = Amount of gumballs
- Volume of a sphere = 4/3 x 3.14 x (radius x radius x radius)
- Volume of a gumball = 4/3 x 3.14 x (0.5 x 0.5 x 0.5) = 0.5235 inches
- ((7.3 x 5 x 9.4) x 5/8) / 0.523 = X
- (343.1 x 5/8) / 0.523 = X
- 214.4375 / 0.523 = X
- 410 = X
Therefore, 410 gumballs will be needed to fill the box.
Learn more in brainly.com/question/1578538
<span>The majority of the scores on the in test are between 85 to 115. This makes the mean 100 and the standard deviation 15. Anyone who scores above or below this range is ether more intelligent or less intelligent then the majority of participants in the test. Since Clara scored 118 she is smarter than most of the adults on this study.</span>
Volume=(4/3)pi(r^3)
radius=1/2diameter
d=36
radius=1/2 36
radius=18
subsitute
volume=4/3 pi 18^3
volume=4/3 pi 5832
volume=23328/3 pi
volume=7776pi
aprox pi to 3.14
volume=7776 times 3.14
volume=24416.64
answer is 24416.64 yd^3
