Simplify the expression: 6 + 3(x + 4) <br>А 6 + 3x + 12 <br>B 9x + 36 <br>C 3x + 18 <br>D 9x + 4

Find the square root of 3.6 upto 2 decimal places. *With Solution I need*

almond37 [142]

Answer:

The square root is 1.90

Step-by-step explanation:

Given

$x = \sqrt{3.6}$

Required

Find x

Express 3.6 as 36/10

So, we have:

$x = \frac{\sqrt{36}}{\sqrt{10}}$

This gives

$x = \frac{6}{\sqrt{10}}$

Rationalize

$x = \frac{6}{\sqrt{10}}*\frac{\sqrt{10}}{\sqrt{10}}$

$x = \frac{6\sqrt{10}}{10}$

Using a calculator

$\sqrt{10} \approx 3.16$

So, we have:

$x = \frac{6*3.16}{10}$

$x = \frac{18.96}{10}$

$x = 1.896$

Approximate

$x = 1.90$

7 0

3 years ago

$18, P = $200, r = ?, t = 1.5 years. Find the annual interest rate.

faust18 [17]

Question 1)

Given

Interest I = $18

Principle P = $200

t = 1.5 years

To determine

Interest rate r = ?

Using the formula

$P = Irt$

$r=\frac{I}{Pt}$

susbtituting I = 18, t = 1.5 and P = 200

$r=\frac{18}{\left(200\times 1.5\right)}$

$r = 0.06$

or

r = 6% ∵ 0.06 × 100 = 6%

Therefore, we conclude that the interest rate required to accumulate simple interest of $18.00 from a principal of $200 over 1.5 years is 6% per year.

Question 2)

Given

Interest I = $60

Principle P = $750

Interest rate = 4% = 0.04

To determine

Time period t = ?

Using the formula to calculate the time period

$P = Irt$

$t\:=\:\frac{P}{Ir}$

$t=\frac{60}{\left(750\times 0.04\right)}$

$t = 2$ years

Therefore, the time required to accumulate simple interest of $ 60.00

from a principal of $ 750 at an interest rate of 4% per year is 2 years.

7 0

2 years ago

You roll two dice. What is the probability that the average of the high and low roll is exactly 3, to four decimal places?

Sladkaya [172]

Answer:

0.1111

Step-by-step explanation:

Given that you roll two dice.

the average of the high and low roll is exactly 3,

Since die can show only 1 to 6 we can say average can be 3 in each of the following case.

(1,5) (2,4) (3,3) (4,2) (5,1)

There cannot be any other combination to get average of 3.

Thus favourable events = 4

Sample space will have

(1,1)...(1,6)

(2,1)....

(6,1)...(6,6) i.e. 36

So probability that the average of the high and low roll is exactly 3

= $\frac{4}{36} \\=0.1111$

8 0

3 years ago

19−6(−k+4) Simplify to create an equivalent expression

almond37 [142]

$\text{Hey there!}\\\\\\\text{In order for you to solve this equation you need to distribute}\\\text{-6(-k) = 6k \& -6(4) = -24}\\\\\text{New equation: 19 + 6k + (-24)}\\\\\text{Combine your like terms (if there is any)}\\\text{(6k(19+(-24)))}\\\text{Your like terms are: 19 + (-24) = -5}$

$\text{Your new equation is: 6k + (-5)}\\\\\text{+ \& - = -}\text{\underline{ (positive \& negative equals negative)}}\\\\\text{The number in the center will be a negative}\\\\\boxed{\boxed{\text{Answer: 6k - 5}}}\checkmark\\\\\\\\\\\text{Good luck on your assignment and enjoy your day!}\\\\\frak{LoveYourselfFirst:)}$