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Luba_88 [7]
2 years ago
11

-2.75 + 8.25 ? Help pls

Mathematics
1 answer:
Archy [21]2 years ago
3 0
The answer is 5.5!!!!
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Find the length of a diagonal<br> of a square with sides of 14<br> feet long.<br> [?][feet<br> /
inessss [21]

Answer:

14√2 feet

Step-by-step explanation:

The length of a diagonal of a square is L=S\sqrt{2} where S is the side length of the square. Therefore, L=14\sqrt{2}.

4 0
2 years ago
How do u write 5.6 as a fraction in simplest form
krok68 [10]
The first answer to your question is 5 6/10 because you pronounce the decimal as six tenths. There is a simpler form of 5 6/10, it is 5 3/5. This is because you divide six by 2 and get 3 and divide 10 by two and get 5. 
5 0
3 years ago
Read 2 more answers
What is this 2x-5+22=?
Scilla [17]
<h2><u>Answer:</u></h2><h2><u></u>\boxed{\boxed{\sf{2x+17}}}<u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Add −5 and 22:</h3>
  • -5+22=17

<em>  - You could also solve this by  flipping the numbers around and subtracting 22 - 5, Which still gives you 17. </em>

<u />

So your answer is \bold{(2x+17)}.

<h3 />

______________________________

<h3 />

7 0
2 years ago
Read 2 more answers
Please help! please.
tamaranim1 [39]
A (-3, -1) 

You know this because QIII is in the bottom left corner and both numbers are negative

5 0
2 years ago
Read 2 more answers
Jamie recently drove to visit her parents who live 510 miles away. On her way there her average speed was 25 miles per hour fast
tino4ka555 [31]

Answer:

       Average speed in mph with which he goes to parent's place = 75 mph

       Average speed with he comes back = 50 mph

Explanation:

  Distance between Jamie's house and parent's house = 510 miles.

  Let u be the average speed in mph with which he goes to their place.

  We have the average speed of coming back = (u -25) mph

  Total time of journey considering both ways = 17 hours.

  Time taken to go their home = 510/u hours

  Time taken for coming back = 510/(u-25) hours

  So total time = \frac{510}{u} +\frac{510}{u-25}

 Equating both times we have

       \frac{510}{u} +\frac{510}{u-25}=17\\ \\ 510u-12750+510u=17u^2-425u\\ \\ 17u^2-1445u+12750=0\\ \\ u^2-85u+750=0\\ \\ (u-75)(u-10)=0

  u = 75 mph or u =10 mph

If the average speed in mph with which he goes to their place = 75 mph, average speed with he comes back = 75-25 = 50 mph

If the average speed in mph with which he goes to their place = 75 mph, average speed with he comes back = 10-25 = -15 mph(Not possible)

So,  Average speed in mph with which he goes to parent's place = 75 mph

       Average speed with he comes back = 50 mph

5 0
2 years ago
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