Answer:
Since the calculated value of z= 1.6279 does not fall in the critical region Z ≥ ±1.96 we conclude that there is no difference between the population variance and the sample variance.
Step-by-step explanation:
The data given is
Population mean μ= $ 7.18
Population variance= σ²= 3.81
Population Standard Deviation = √σ²= √3.81= 1.952
Sample Mean= x`= $ 8.02
Sample Standard Deviation =s = $ 2.08
Sample Size = 15
Significance Level = ∝= 0.05
The null and alternate hypotheses are
H0: σ1=σ2 against the claim that Ha: σ1≠ σ2
where σ1 is the population variance and
σ2 is the sample variance
The rejection region is Z ≥ ±1.96 for two tailed test at ∝= 0.05
The test statistic z is used
z= x`- μ/ σ/√n
Putting the values
Z= 8.02-7.18/1.952/√15
z= 0.84/0.51599
z= 1.6279
Since the calculated value of z= 1.6279 does not fall in the critical region Z ≥ ±1.96 we conclude that there is no difference between the population variance and the sample variance.
To find in how many ways this can be done, we can use the method of combination.
As the customer have to choose 2 out of 3 appetizers, the combination would be 3C2.
For 4 out of 5 main courses, the combination wouls be 5C4.
For 6 out of 8 desserts, the combination would be 8C6.
We can then combine them into a single equation to find the answer:
3C2 x 5C4 x 8C6
=420
Therefore, the answer is 420 ways.
Hope it helps!
Answer:
Step-by-step explanation:
Center is at (3, -4) and the radius is 2
