Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
Answer:
if the * is equal to multiply, the answer is 12
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
because when you divide with the coeficient it sums out to be 7
Haha, you first start off with adding 3 to both sides, cancelling the -3, and adding it to 9. you end up with 5x=12, in which you divide both sides by 5. you get 2 and 2/5 or 12/5! hope that helps :)
Answer:
1, 2, 4, 8, 16.
Step-by-step explanation:
Have a good day hope this helps can get a brainiest? Stay Safe!
