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Luba_88 [7]
4 years ago
6

Hel0 me please, please please​

Mathematics
1 answer:
Simora [160]4 years ago
8 0

Answer:

The answer would be 0

Step-by-step explanation:

Go to symbolab.com and just put the equation in

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The number of different species of plants in some gardens is recorded.
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(a) The mean of the number of different species of plants in some gardens is 4.5 .

(b) The standard deviation of the number of different species of plants in some gardens is 2.12 (Approximately)

It is given in the question that the number of different species recorded are:-

1 2 3 4 4 5 5 6 7 8

We have to find the mean and standard deviation of the given data of the number of plants of different species.

(a) We know that, the formula for mean is :-

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Hence,

Mean = \frac{1+2+3+4+4+5+5+6+7+8}{10} =\frac{45}{10}=4.5

(b) Standard deviation = \sqrt{\frac{Sum(X-m)^{2} }{N}  }

Where,

X = each value

m = mean

N = number of values

Hence,

Sum(X-m)^{2} =(1-4.5)^{2}+(2-4.5)^{2}+ (3-4.5)^{2}+ (4-4.5)^{2}+ (4-4.5)^{2}+ (5-5.5)^{2}+ (5-5.5)^{2}+ (6-5.5)^{2}+ (7-5.5)^{2}+ (8-5.5)^{2}\\ \\ Sum(X-m)^{2}=(-3.5)^{2} +(-2.5)^{2}+ (-1.5)^{2}+ (-0.5)^{2}+ (-0.5)^{2}+ (0.5)^{2}+ (0.5)^{2}+ (1.5)^{2}+ (2.5)^{2}+ (3.5)^{2} \\\\

Sum(X-m)^2=12.25+6.25+2.25+0.25+0.25+0.25+0.25+2.25+6.25+12.25\\\\=42.5

Standard deviation = {\sqrt{\frac{{42.25}}{10} }} =\frac{6.7}{\sqrt{10} }=\frac{6.7}{3.16}=2.12  (approximately).

To learn more about mean, here:-

brainly.com/question/13451489

#SPJ4

4 0
1 year ago
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