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3 years ago

Simplify the expression. (x^1/15)^5

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

5 0

The exponent is (1/15)(5), which leads to 1/3.

We now have x^(1/3), which is equivalent to the cube root of x.

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Find the volume of a rectangular prism if the length is 4x, the width is 2x, and the height is x3 + 3x + 6. Use the formula

MaRussiya [10]

8x2(x3 + 3x + 6)

8x5 + 25x3 + 48x2

8 0

4 years ago

Read 2 more answers

Write the ratio in simplest form 60/45

Bond [772]

Answer: BRAINLIEST PLZ

4/3

Step-by-step explanation:

60/45 => both divisible by 15

60÷15=4

45÷15=3

4/3 is the answer!!

BRAINLIEST PLZ

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3 years ago

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George has a small coin collection. He has collected 16 gold coins, 28 silver coins, 32 copper coins, and 4 bronze coins. At a f

irakobra [83]

First you add up the number of coins in total so:
16+28+32+4
which equals: 80
Then to find 15% you have to do this:
80 divided by 100 then multiply by 15 which is 12.
The answer is 12.

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3 years ago

How many business students must be randomly selected to estimate the mean monthly earnings of business students at one college?

marysya [2.9K]

Answer:

Approximately 63 business students must be randomly selected to estimate the mean monthly earnings of business students at one college

Step-by-step explanation:

confidence interval = 95%

Standard deviation $(\sigma )$ = 569

$\alpha$ = 1 - 0.95 = .05

$Z_{\frac{\alpha }{2}}$ = $Z_{\frac{.05 }{2}}$ = 1.96

We want 95% confidence that the sample mean is within $140 of the population mean

margin of error ( E ) =140

let n be the sample size

margin of error ( E ) = $Z_{\frac{\alpha }{2}}\frac{\sigma }{\sqrt{n}}$

squarring both side

$E^{2} = 1.96^{2}\times\frac{\sigma ^{2}}{n}$

$n = \frac{1.96^{2}}{140^{2}}\times 569^{2}$

n = 63.45

n =63 approximately

8 0

4 years ago

Which table shows a function that is increasing only over the interval (–2, 1), and nowhere else?

Novosadov [1.4K]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Any feature increases when y-value should likewise be increased for the growth of x-values

Each table will be checked

table-1:

That we can see

-3, -2,-1 , 0, 1,2 x increase

And also -6,-3,-1,1,3,6 y increase

It increases, thus,

table-2:

That we can see

-3, -2,-1 , 0, 1,2 x increase

But between -2 and 1, it's asking

The y-values of -4,-1,1,4..... are increasing

This increases, thus,

table-3:

Which we can see

-3, -2,-1 , 0, 1,2 x increase

But y changes between -3 and -5 .....this decreases

This does not increase, thus,

table-4:

we can find that the x increase to -3, -2, -1, 0, 1,2 however y rises from 7 to 1.....

This does not increase, thus,

8 0

3 years ago