Question

A 0.316 mol sample of nitrogen gas, N2 (g), is placed in a 4.00 L container at 315 K.

Answer 1

2.04 atm is the pressure of the nitrogen gas in the container when 0.316 mol sample of nitrogen gas, N2 (g), is placed in a 4.00 L container at 315 K.

Explanation:

Data given:

moles of nitrogen gas, n = 0.316

volume of the nitrogen gas, V = 4 litres

temperature of the container of nitrogen gas  = 315 K

R (gas constant) = 0.08201 Latm/mole K

Pressure of the nitrogen gas on the container,  P = ?

from the data given, we will apply ideal gas law equation to calculate the pressure on the nitrogen gas:

PV = nRT

Rearranging the equation,

P = $\frac{nRT}{V}$

P = $\frac{0.316 X 0.08201 X 315}{4}$

P = 2.04 atm

The pressure of the nitrogen gas in the container is 2.04 atm.