Answer:
Follows are the solution:
Explanation:
A + B = C
Its response decreases over time as well as consumption of a reactants.
r = -kAB
during response A convert into 2x while B convert into x to form 3x of C
let's y = C
y = 3x
Still not converted sum of reaction
for A: 100 - 2x
for B: 50 - x
Shift of x over time
Integration of x as regards t
![\frac{1}{[(100 - 2x)(50 - x)]} dx = -k dt\\\\\frac{1}{2[(50 - x)(50 - x)]} dx = -k dt\\\\\ integral\ \frac{1}{2[(50 - x)^2]} dx =\ integral [-k ] \ dt\\\\\frac{-1}{[100-2x]} = -kt + D \\\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5B%28100%20-%202x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5C%20integral%5C%20%20%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%5E2%5D%7D%20dx%20%3D%5C%20integral%20%5B-k%20%5D%20%5C%20dt%5C%5C%5C%5C%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%5C%5C%5C%5C)
D is the constant of integration
initial conditions: t = 0, x = 0
![\frac{-1}{[100-2x]} = -kt + D \\\\\frac{ -1}{[100]} = 0 + D\\\\D= \frac{-1}{100}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%20%20%5C%5C%5C%5C%5Cfrac%7B%20-1%7D%7B%5B100%5D%7D%20%3D%200%20%2B%20D%5C%5C%5C%5CD%3D%20%5Cfrac%7B-1%7D%7B100%7D%5C%5C%5C%5C)
hence we get:
![\frac{-1}{[100-2x]}= -kt -\frac{1}{100}\\\\or \\\\ \frac{1}{(100-2x)} = kt + \frac{1}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%3D%20-kt%20-%5Cfrac%7B1%7D%7B100%7D%5C%5C%5C%5Cor%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B%28100-2x%29%7D%20%3D%20kt%20%2B%20%5Cfrac%7B1%7D%7B100%7D)
after t = 7 minutes , 
Insert the above value x into 
equation 
to get k.
therefore plugging in the equation the above value of k
Let y = C
, calculate C:
y = 3x
amount of C formed in 28 mins
plug t = 28
therefore amount of C formed in 28 minutes is = 3x = 144.78 grams
C:
y= 136.5 =137
Answer:
The mass of one mole of a substance is equal to that substance's molecular weight. ... water is 18.015 atomic mass units (amu), so one mole of water weight 18.015 grams. ... Avogadro's number is a proportion that relates molar mass on an atomic ... one molecule of water (H2O), one mole of oxygen (6.022×1023 of O atoms)
Answer:
10
x
^3
−
10
x
^2
+
10
x
−
12
Explanation:
Considering that CCL3F gas behave like an ideal gas then we can use the Ideal Gas Law
<span>PV = nRT, however is an approximation and not the only way to resolve this problem with the given data..So,at the end of the solution I am posting some sources for further understanding and a expanded point of view. </span>
<span>Data: P= 856torr, T = 300K, V= 1.1L, R = 62.36 L Torr / KMol </span>
<span>Solving and substituting in the Gas equation for n = PV / RT = (856)(1.1L) /( 62.36)(300) = 0.05 Mol. This RESULT is of any gas. To tie it up to our gas we need to look for its molecular weight:MW of CCL3F = 137.7 gm/mol. </span>
<span>Then : 0.05x 137.5 = 6.88gm of vapor </span>
<span>If we sustract the vapor weight from the TOTAL weight of liquid we have: 11.5gm - 6.88gm = 4.62 gm of liquid.d</span>
Explanation:
An atom undergoes alpha decay by losing a helium atom.
So when bismuth undergoes alpha decay, we have;
²¹⁰₈₃Bi --> ⁴₂He + X
Mass number;
210 = 4 + x
x = 206
Atomic number;
83 = 2 + x
x = 81
The element is Thallium. The symbol is Ti.
For the second part;
X --> ⁴₂He + ²³⁴₉₀Th
Mass number;
x = 4 + 234 = 238
Atomic Number;
x = 2 + 90 = 92
The balanced nuclear equation is;
²³⁸₉₂U --> ⁴₂He + ²³⁴₉₀Th
