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Veseljchak [2.6K]
3 years ago
10

What is 39,265 to the nearest ten thousand

Mathematics
1 answer:
Kamila [148]3 years ago
7 0

Answer:

40,000 is 39,265 rounded to the nearest ten thousands

Step-by-step explanation:

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What is another way to write 54?
never [62]

Answer:

None of the above.

5 0
3 years ago
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When x=1/2, what is the value of 8x-3/x
Viefleur [7K]
8x - 3/x

x = 1/2

(8 • 1/2) - 3/0.5

4 - 1.5

2.5
6 0
3 years ago
Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
PLEASE ANSWER! URGENT
Lorico [155]
There would be 2034 students competing in 2012.

We can write a simple equation to find this answer. Let X, be the number of students starting in 2012. Then, we multiply by 0.9 and 1.1 to get to 2014. To work backwards, just divide by 1.1, then by 0.9.

2014 / 1.1 / 0.9 = 2034
4 0
3 years ago
(3 points)
Snezhnost [94]

Answer:

The exponential Function is 20+12h=200.

Farmer will have 200 sheep after <u>15 years</u>.

Step-by-step explanation:

Given:

Number of sheep bought = 20

Annual Rate of increase in sheep = 60%

We need to find that after how many years the farmer will have 200 sheep.

Let the number of years be 'h'

First we will find the Number of sheep increase in 1 year.

Number of sheep increase in 1 year is equal to Annual Rate of increase in sheep multiplied by Number of sheep bought and then divide by 100.

framing in equation form we get;

Number of sheep increase in 1 year = \frac{60}{100}\times20 = 12

Now we know that the number of years farmer will have 200 sheep can be calculated by Number of sheep bought plus Number of sheep increase in 1 year multiplied by number of years  is equal to 200.

Framing in equation form we get;

20+12h=200

The exponential Function is 20+12h=200.

Subtracting both side by 20 using subtraction property we get;

20+12h-20=200-20\\\\12h=180

Now Dividing both side by 12 using Division property we get;

\frac{12h}{12} = \frac{180}{12}\\\\h =15

Hence Farmer will have 200 sheep after <u>15 years</u>.

6 0
3 years ago
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