9514 1404 393
Answer:
c. 1150 square units
Step-by-step explanation:
The sum of the two side lengths is half the perimeter, so is 125/2 = 62.5 units. The long side is 4/5 of that, so is 50 units.
The area is the product of the long side and the height to the long side:
A = bh
A = (50 units)(23 units) = 1150 units²
__
<em>Additional comment</em>
This geometry is impossible, because the height from the long side cannot be more than the length of the short side. Here, the short side is 12.5 units, so it is not possible for the height to be 23 units.
If the height is measured from the short side, then the area is 287.5 square units.
The area of a triangle can be found using the formula 1/2bh, where the variable b represents the value of the base and the variable h represents the value of the height.
1) there were 32 bales added
2) 8 hours
3) 74 cards
4) 11 packs
5) $57
6) ummm...$3?
7) began with 12
8) $5 per candy bar
9) 44 students on each bus
10) $77 spent on baseball gear
Let y(t) represent the level of water in inches at time t in hours. Then we are given ...
y'(t) = k√(y(t)) . . . . for some proportionality constant k
y(0) = 30
y(1) = 29
We observe that a function of the form
y(t) = a(t - b)²
will have a derivative that is proportional to y:
y'(t) = 2a(t -b)
We can find the constants "a" and "b" from the given boundary conditions.
At t=0
30 = a(0 -b)²
a = 30/b²
At t=1
29 = a(1 - b)² . . . . . . . . . substitute for t
29 = 30(1 - b)²/b² . . . . . substitute for a
29/30 = (1/b -1)² . . . . . . divide by 30
1 -√(29/30) = 1/b . . . . . . square root, then add 1 (positive root yields extraneous solution)
b = 30 +√870 . . . . . . . . simplify
The value of b is the time it takes for the height of water in the tank to become 0. It is 30+√870 hours ≈ 59 hours 29 minutes 45 seconds
