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Roman55 [17]
3 years ago
14

Free wifi is typically offered on an a) unencrypted b) encrypted c) open d) private

Computers and Technology
2 answers:
aliya0001 [1]3 years ago
7 0

c) open

I think this because when you're in an open space (such as starbucks) it's public for anyone to enter. I think.

Greeley [361]3 years ago
3 0

Answer:

open

Explanation:

Free WiFi is typically offered in an open place ( public place ) as a form of attracting people to the place.some of the reasons public places offer such services like free WiFi is to ensure customer satisfaction and also to encourage customers to stay longer and also return in the future.

A free WiFi is a WiFi network that is not encrypted i.e unencrypted ( no password is required to be connected to it ) most WiFi networks on private spaces/properties are usually not free to avoid unauthorized access/connection to the WiFi

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Why might a business choose a server-based network over a peer-to-peer network?
valina [46]

Answer:

Hope this helps you out    Answer: Greater security

Explanation:

Server maintains better relationship with server at everry time. So it gives maximum of security and reliability against unauthorised access

3 0
3 years ago
Declare a structure with a type name: Car containing:
OLga [1]

Answer:

C++ code is given below

Explanation:

#include <iostream>

#include <cctype>

#include <string.h>

#include <cstring>

#include <sstream>

using namespace std;

struct Car {

public:    

char reportingMark[5];    

int carNumber;

string kind;

bool loaded;

string destination;

};

void input(Car *);

void output(Car *);

int main() {

Car *T = new Car;    

input(T);

output(T);    

delete T;    

return 0;

}

void input(Car *T)

{

string str, s;

cout << " Enter the reporting mark as a 5 or less character uppercase string: ";

cin >> str;

for (int i = 0; i < str.length(); i++)

T->reportingMark[i] = toupper(str[i]);

cout << " Enter the car number: ";

cin >> T->carNumber;

cout << " Enter the kind: ";

cin >> T->kind;

cout << " Enter the loaded status as true or false: ";

cin >> s;    

istringstream(s) >> boolalpha >> T->loaded;    

if (T->loaded == true) {

cout << " Enter the destination: ";

cin.ignore();

getline(cin, T->destination);

}

else

T->destination = "NONE";    

}

void output(Car *T)

{

cout << " Reporting Mark: " << T->reportingMark;

cout << " Car Number: " << T->carNumber;    

cout << " Kind: " << T->kind;

cout << " Loaded Status: " << boolalpha << T->loaded;

cout << " Destination: " << T->destination << " ";

}

7 0
4 years ago
In the airline industry, frequent flyer programs, ticket kiosks, and e-ticketing are all examples of capabilities that are _____
crimeas [40]

Answer:

valuable; rare

Explanation:

A valuable capability is that which gives a firm some competitive advantage. Core competencies are the operational activities that a company does best. A business’s core competencies are what distinguish it from other rival companies in its industry. While Rare capabilities are capabilities that a small amount of, if any, competitors possess. Those type of capabilities that are costly or impossible to imitate.

from the above explanation we can deduce that the modern technology implementation in the airline industry has made it possible to have valuable ptograms and softwares for carring out several task which are no longer scarce to procure.

7 0
3 years ago
When a vehicle strikes a pedestrian, it's most often during A. a period of darkness or low visibility B. the day when pedestrian
yuradex [85]

Answer:

A. a period of darkness or low visibility

Explanation:

When a vehicle strikes a pedestrian, it's most often during a period of darkness or low visibility.

8 0
4 years ago
Read 2 more answers
For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are
Sauron [17]

Answer:

lw $t0, 16($s7) // $t0 = B[4]

lw $t1, 12($s7) // $t1 = B[3]

sub $t0, $t0, $t1 // $t0 = B[4] – B[3]

sll $t0, $t0, 2 // $t0 = $t0 * 4

add $t0, $t0, $s6 // $t0 = &A[B[4] – B[3]]

lw $t1, 0($t0) // $t1 = A[B[4] – B[3]]

add $s0, $s1, $t1 // f = g + A[B[4] – B[3]

Explanation:

lw $t0, 16($s7) // $t0 = B[4]

lw $t1, 12($s7) // $t1 = B[3]

sub $t0, $t0, $t1 // $t0 = B[4] – B[3]

sll $t0, $t0, 2 // $t0 = $t0 * 4

add $t0, $t0, $s6 // $t0 = &A[B[4] – B[3]]

lw $t1, 0($t0) // $t1 = A[B[4] – B[3]]

add $s0, $s1, $t1 // f = g + A[B[4] – B[3]

6 0
3 years ago
Read 2 more answers
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