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Sav [38]
4 years ago
14

You shuffle a standard 52 card deck of cards, so that any order of the cards is equally likely, than draw 4 cards. How many diff

erent ways are there to make that draw, where you care about the order
Mathematics
1 answer:
galina1969 [7]4 years ago
7 0

Answer:

270725 different ways

Step-by-step explanation:

The problem tells us that the order of the letters does not matter. Therefore, in the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

We have to n = 52 and r = 4

C (52, 4) = 52! / 4! * (52-4)! = 52! / (4! * 48!) = 270725

Which means that there are 270725 different ways in total to make that raffle

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Here's what we'll be evaluating:  

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Step-by-step explanation:

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