The transformations are
- (b) A vertical shift 16 units downward.
- (d) A horizontal shift 16 units to the right
<h3>How to determine the transformation?</h3>
The functions are given as:
f(x) = x
g(x)= x - 16
When a function is shifted right, the transformation rule is:
(x, y) = (x - h, y)
This means that the transformation is (d) A horizontal shift 16 units to the right
Since the parent function is a base linear function.
The transformation can also be represented as:
(x, y) = (x, k - h)
This gives
g(x)= x - 16
This means that the transformation is (b) A vertical shift 16 units downward.
Hence, the transformations are (b) and (d)
Read more about transformation at:
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4x=-3y+17 becomes 4x+3y=17
4x+3y=17
3x-4y=-6
alrighty
elimination
muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them
25x+0y=50
25x=50
idivide both sides by 25
x=2
sub back
3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3
(x,y)
(2,3)
The answer is 221. And it’s solved with PEMDAS
Answer:
(D). 182
Step-by-step explanation:
did the math
Answer:
The probability will be 0.3085 or 0
Step-by-step explanation:
Given:
True mean=12.5
Sample mean =12.6
Standard deviation=0.2
Samples=100
To Find:
Probability that exceeds 12.6 ounces.
Solution:
Calculate the Z-score for given means and standard deviation.
So
Z-score= (true mean -sample mean)/standard deviation.
Z-score=(12.5 -12.6)/0.2
=-0.1/0.2
=-0.5
Now Using Z-table
P(X≥-0.5)=p(Z≥-0.5)=0.3085
Hence Probability that sample mean weight exceeds will be 0.3085
OR
By using Normal distribution with sampling ,it will be as follows
Z=(X-u)/[Standard deviation/Sqrt(No of samples)]
Z=(12.6-12.5)/(0.2/Sqrt(100)
Z=0.1/0.2/10
Z=5
So P(X≥12.6 )=P(Z≥5)=1
Pr(Z≥5)=1-1=0.
(Refer the attachment )
Hence Probability of getting ounces greater than 12.6 is '0'.
The sampling is of 0.02 size hence graphically it looks likely.
as shown in attachment.