Answer:
Step-by-step explanation:2+2=4
Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
1
Step-by-step explanation:
you move the decimal to the right twice, so it goes from .01 to 1.00 if that makes sense :)
LN=8 because every time there is a midpoint you have to divide it in half. So 64,32,16,8
