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lilavasa [31]
3 years ago
6

Find the value of the following expression:

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
3 0

Answer:

4

Step-by-step explanation:

Kazeer [188]3 years ago
3 0
The answer is 4 I hope this helps
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Elizabeth and lauren sold cookies for a school fundraiser and made 1,316.70. Together the girl sold a total of 831 cookies. Eliz
wlad13 [49]

Answer:

468

Step-by-step explanation:

831-x would be the equation to find the amount of peanut butter cookies. You'd plug this into the equation to find the amount of cookies in relation to money meaning your equation is 1.5x+1.65(831-x)=1316.7. You then simplify and solve to find 468

6 0
3 years ago
Please help asap 15 points
zubka84 [21]

the second option.


(3h+18)+(15h)=180

-18 . -18

3h . + 15h=162

18h=162

162/18 = 9

4 0
3 years ago
Read 2 more answers
What is the volume of a rectangular prism with a length of 1. 4 meters, a width of 0. 5 meter, and a height of 1. 8 meters? 7. 5
mihalych1998 [28]

The volume of the rectangular prism will be  V=1.26m^{3}

<h3>What will be the volume of the rectangular prism ?</h3>

Given that

\rm Lenth \ of \ the \ rectangular \ prism =1.4\ m

\rm width\ of \ prism=0.5\ m

\rm Height \ of \ prism=1.8\ m

\rm Volume \ of \ the \ Rectangular \ Prism= L\times W\times H

V=1.4\times 0.5\times1.8=1.26 \ m^{3}

Thus the volume of the rectangular prism will be  V=1.26m^{3}

To know more about the volume of the rectangular prism follow

brainly.com/question/24284033

6 0
2 years ago
Which equations represent the function?
hammer [34]
The answer would be D
7 0
2 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
3 years ago
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