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3 years ago

Find the value of the following expression:

Mathematics

2 answers:

Ira Lisetskai [31]3 years ago

3 0

Answer:

Step-by-step explanation:

Kazeer [188]3 years ago

3 0

The answer is 4 I hope this helps

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Elizabeth and lauren sold cookies for a school fundraiser and made 1,316.70. Together the girl sold a total of 831 cookies. Eliz

wlad13 [49]

Answer:

468

Step-by-step explanation:

831-x would be the equation to find the amount of peanut butter cookies. You'd plug this into the equation to find the amount of cookies in relation to money meaning your equation is 1.5x+1.65(831-x)=1316.7. You then simplify and solve to find 468

6 0

3 years ago

Please help asap 15 points

zubka84 [21]

the second option.

(3h+18)+(15h)=180

-18 . -18

3h . + 15h=162

18h=162

162/18 = 9

4 0

3 years ago

Read 2 more answers

What is the volume of a rectangular prism with a length of 1. 4 meters, a width of 0. 5 meter, and a height of 1. 8 meters? 7. 5

mihalych1998 [28]

The volume of the rectangular prism will be $V=1.26m^{3}$

<h3>What will be the volume of the rectangular prism ?</h3>

Given that

$\rm Lenth \ of \ the \ rectangular \ prism =1.4\ m$

$\rm width\ of \ prism=0.5\ m$

$\rm Height \ of \ prism=1.8\ m$

$\rm Volume \ of \ the \ Rectangular \ Prism= L\times W\times H$

$V=1.4\times 0.5\times1.8=1.26 \ m^{3}$

Thus the volume of the rectangular prism will be $V=1.26m^{3}$

To know more about the volume of the rectangular prism follow

brainly.com/question/24284033

6 0

2 years ago

Which equations represent the function?

hammer [34]

The answer would be D

7 0

2 years ago

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago