20x = 21x-3
-x= -3
x= 3
20(3)= 60°
21(3)-3= 63-3= 60°
the answer to the question is b
Given:
<em>x </em>intercepts of a quadratic equation are 3 and 4.
The objective is to find the quadratic equation.
The <em>x</em> intercepts can be written as,
Similarly,
Now, multiply both the term to get the quadratic equation.
Hence, the required quadratic equation is obtained.
The first thing you need to do is find the radius of the semicircle. To do that you look to see that the width of the rectangle is the same as the radius. Once you have the Area of a Semicircle calculated multiply it by 3. then, we know that the other length of the rectangle is 3 diameters of a semicircle this means that you multiply the radius of 7 by 6 which gives you 42. You take the area of the rectangle (294) and subtract the area of the 3 semicircles(230.79) Which gives you the answer of 63.21cm^2
Hi the answer to this is
A - Vertical Asymptote
The answer is $450
If 20 pesos = $1, simply divide 9000 by 20 to get 450
Or do my way and divide 9000 by 10 to get 900 then divide by 2 to get 450
So the answer is $450