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Harman [31]
3 years ago
6

What is 30-5 ( 6+3) 3 power of 22 If you help brainliest

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0

Answer:

35 ig it is correct i tried my best

Step-by-step explanation:

Dmitrij [34]3 years ago
7 0
The answer is 35 :)))




goood luckkk
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Forth time I had to ask this!!
lubasha [3.4K]
A.) Yes you can, the expression would be (2.95 x Y) + 4 = X
B.) (2.95 x 24) + 4 = $74.80
C.) (2.95 x 57) + 4 = X
2.95 x 57 = 168.15 + 4 = 172.15
so basically they can buy 57 books without going over $175
7 0
3 years ago
The ratio of the perimeters of two similar triangles is 4:7. What is the area of each of these triangles if the sum of their are
Mashcka [7]

Answer:

The area of triangles are 16 cm^2 and 49 cm^2

Step-by-step explanation:

we know that

If two figures are similar, the ratio of its perimeters is equal to the scale factor and the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the smaller triangle in square centimeters

y ----> the area of the larger triangle in square centimeters

we know that

z=\frac{4}{7}

\frac{x}{y}=z^2

so

\frac{x}{y}=(\frac{4}{7})^2      

\frac{x}{y}=\frac{16}{49}

x=\frac{16}{49}y -----> equation A

x+y=65 ----> equation B

solve the system by substitution

substitute equation A in equation B

\frac{16}{49}y+y=65

solve for y

\frac{65}{49}y=65

y=49\ cm^2

Find the value of x

x=\frac{16}{49}(49)

x=16\ cm^2

therefore

The area of triangles are 16 cm^2 and 49 cm^2

3 0
4 years ago
Read 2 more answers
A triangular bookshelf has a base of 10 inches, 12 inches, and 18 inches. Will the bookshelf fit in the corner of a square livin
Delicious77 [7]

Answer:

Not possible

Step-by-step explanation:

Since the triangular base has not a right-angled form. That is, the longest side is greater than value of hypotenuse, meaning that triangular base has a form of a obtuse-angle triangle.

  1. 10² + 12² = 18²        It is not possible because they dont equal
  2. 100+ 144= 324
  3. 244≠ 324
5 0
4 years ago
Fit a quadratic function to these three points: (-2,8)(0,-4),and (4,68)
aev [14]
Given three points
P1(-2,8)
P2(0,-4)
P3(4,68)
We need the quadratic equation that passes through all three points.

Solution:
We first assume the final equation to be
f(x)=ax^2+bx+c .............................(0)

Observations:
1. Points are not symmetric, so cannot find vertex visually.
2. Using the point (0,-4) we substitute x=0 into f(x) to get
f(0)=0+0+c=-4, hence c=-4.
3. We will use the two other points (P1 & P3) to set up a system of two equations to find a and b.
f(-2)=a(-2)^2+b(-2)-4=8 => 4a-2b-4=8.................(1)
f(4)=a(4^2)+b(4)-4=68 =>  16a+4b-4=68.............(2)
4. Solve system
2(1)+(2) => 24a+0b-12=84 => 24a=96 => a=96/24 => a=4 ......(3)
substitute (3) in (2) => 16(4)+4b-4=68 => b=8/4 => b=2  ..........(4)
5. Put values c=-4, a=4, b=2 into equation (0) to get

f(x)=4x^2+2x-4

Check:
f(-2)=4((-2)^2)+2(-2)-4=16-4-4=8
f(0)=0+0-4 = -4
f(4)=4(4^2)+2(4)-4=64+8-4=68
So all consistent, => solution ok.

6 0
4 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!
Mamont248 [21]

Answer: x < -4 and -4 > x

x < -4 would be one of the two options.

This means that any number less than -4 is a solution.

This is shown by drawing an open dot on -4 and then

drawing an arrow to the left shows all answer less tan 4.

-4 > x would be our second option.

We can change it to say x < -4.

All I did was changed the order of numbers and switched the sign.

So x < -4 is the same as the first option.

8 0
3 years ago
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