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shutvik [7]
3 years ago
14

2 1. Lucy has 4 cups of sugar and her cookie recipe calls for 3 cup of sugar. How many cups of sugar will 1 she have left after

making her cookies?​
Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

1 cup

Step-by-step explanation:

Lucy has 4 cups. She uses 3 cups. She has 1 left. (4-3=1)

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PLZ HELP I PROMISE I WILL GIVE BRAINLIEST!!!! ASAP
irga5000 [103]

Answer:

4c^{7}d^{13}

Step-by-step explanation:

(2cd^{4} )^{2} *(cd)^{5}

4c^{2}d^{8} *c^{5} d^{5}

4c^{7}d^{13}

4 0
3 years ago
What number goes into 88 and 60 both
almond37 [142]
2 and 4 because we all now 2 because every even number is in 2 and 88 divide 4 is 22 and 60 divide 4 is 15
7 0
3 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
How many Tables are needed to make a long table that will seat 22 people
nignag [31]
How long are the tables
6 0
3 years ago
Solve the system of equations by substitution.
n200080 [17]

Answer:

x = -8

y = -6

Step-by-step explanation:

y = -2x - 22

y = x + 2

x + 2 = -2x - 22

x + 2x = -22 - 2

3x = -24

x = -24 : 3

x= -8

y = -8 + 2

y = -6

4 0
2 years ago
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