Answer:
This is the concept of geometry, we are required to calculate for the length of the sides of the rhombus; we know that a rhombus is a compressed square, this implies that all the sides are equal;
If one of the angles is 110° the other angle will be:
180-110=70°
thus using the cosine rule we can find the side lengths as follows;
c^2=a^2+b^2-2ac Cos C
thus
let side a=b=x in
shorter diagonal=c=4 in
C=70°
substituting this into the formula we get:
4^2=x^2+x^2-2*x*x Cos 70
4^2=2x^2-2x^2(0.3420)
16=2x^2-2x^2(0.3420)
dividing through by 2 we get;
8=x^2-0.3420x^2
8=0.6580x^2
x^2=12.15843
getting the square root of both sides get:
x=sqrt(12.15843
x=3.4869)
x=3.5 (1 d.p)
the length of the sides is 3.5
Answer: Depends on how many cubes were used
Step-by-step explanation:
Answer:
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Answer:
88%
Step-by-step explanation:
100% - 12% = 88%
According to the model, the year will the population exceed 470 million is 2060
What is the first step to take?
The first step in this case is to use the model to compute the population figure in each year as shown below:
N = 3.21t + 277.3
Year 2020:
t=20
N = 3.21(20) + 277.3
N=341.50
Year 2025:
t=25
N = 3.21(25) + 277.3
N= 357.55
Year 2030:
t=30
N = 3.21(30) + 277.3
N=373.60
Year 2035:
t=35
N = 3.21(35) + 277.3
N= 389.65
Year 2060:
t=60
N = 3.21(60)+ 277.3
N= 469.90
Year 2065:
t=65
N = 3.21(65)+ 277.3
N= 485.95
Since all the years given do not give the correct year, let us equate the target population figure to the model and solve for t
470= 3.21t + 277.3
470-277.3=3.21t
192.70=3.21t
t=192.70/3.21
t=60.03(approximately 2060)
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