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Sliva [168]
3 years ago
15

Do the ratios 6/3 and 14/7 perform a ratio​

Mathematics
1 answer:
Mazyrski [523]3 years ago
6 0

Answer:

The answer is Yes

Step-by-step explanation:

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What is m∠Q ?
ddd [48]
Unlike the previous problem, this one requires application of the Law of Cosines.  You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines:  a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

                           40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math.  Solve for cos Q, and then find Q in degrees and Q in radians.

7 0
3 years ago
Read 2 more answers
If p:q=2/3:3 and p:r=3/4:2/3 calculate the ratio p:q:r. Giving the answer in its simplest form
adelina 88 [10]

Answer:

Given  

if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form

We need to find the ratio p:q:r

Given p:q = 2/3 : 3 = 2/3 / 3  = 2/9

and p : r = 3/4 : 1/2 = 3/4 / 1/2  = 3/2  

Now p/q = 2/9 and p/r = 3/2

We need to make p equal numerators so we get

p/q = 2/9 x 3/3 = 6/27 and

p/r = 2/3 x 3/2 = 6/4

Therefore p : q : r = 6 : 27 : 4

6 0
3 years ago
The answers are either: 12, 2, 8, or 10 please helppp
blsea [12.9K]

Answer: 10 I believe

Step-by-step explanation:

3 0
3 years ago
A linear regression is done on data the line of best fit is y= 1.25x-6.25. What is the residual for the point (1,1)?
Damm [24]

Answer:

6

Step-by-step explanation:

Find the predicted y value when x=1:

\hat{y}=1.25x-6.25\\\hat{y}=1.25(1)-6.25\\\hat{y}=1.25-6.25\\\hat{y}=-5

Find the residual:

\text{Residual}=\text{Actual Value}-\text{Predicted Value}\\\text{Residual}=y-\hat{y}\\\text{Residual}=1-(-5)\\\text{Residual}=1+5\\\text{Residual}=6

Because our residual is positive, this is an indicator that our predicted y value is too low.

6 0
2 years ago
What is the sum of the first 4 terms of a geometric sequence that has a first term of 2 and a ratio (multiplier) of 8?
taurus [48]

\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ a_1=2\\ r=8\\ n=4 \end{cases} \\\\\\ S_4=2\left( \cfrac{1-8^4}{1-8} \right)\implies S_4=2\left( \cfrac{-4095}{-7} \right) \\\\\\ S_4=2(585)\implies S_4=1170

6 0
3 years ago
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