Hello!
To graph this, you will want to create two points based off of the equation. You plug an x-value into the equation, and you put the y-value outcome with it as an ordered pair. You do this twice, giving you two points to connect.
For example, let's plug in an x-value 1, giving us (1,y)
y= 1-3 (We remove the absolute value)
y=-2 (Subtract)
This gives us one point, (1,-2)
Let's try using -2 as another point.
y= 2-3 (Remove absolute value)
y= -1 (Subtract)
This gives us the point (-2,-1)
To graph, you would draw a straight line through the points (1,-2) and (-2,-1). Note you could do this with any x-value and you would get the same line.
I hope this helps!
(4 x 100) + (1 x 10) + (2 x 1) + (6 x 0.1) + (3 x 0.01) + (8 x 0.001)
The answer is B because 40 goes into 220 5.5 times...
This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
a=-7.3, b=8.25, c=2.1
t=[-8.25+/-sqrt[8.25^2+4*7.3*7.1]/(-2*7.3)
t= -0.572
or
t=1.702
since there is not negative time we take the time taken for the ball to hit the ground will be: t=1.702 sec
Answer:
A. 23+(6-1)x-3
B. 93
Step-by-step explanation:
a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference
6th row = 23 + (6 - 1) x -3
= 23 + (5) x -3
= 23 + (-15)
= 8 - number of boxes in the top row.
b) Sum = N/2[2F + (N - 1) x D]
= 6/2[2*23 + (6 - 1) x -3]
= 3 [46 + (5) x -3 ]
= 3 [46 + -15 ]
= 3 [ 31 ]
= 93 - total number of boxes in the entire display.
Hope this helps! Its 3:25 AM for me too so I know how you feel.
