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svet-max [94.6K]
4 years ago
8

What is the range of this data set?

Mathematics
2 answers:
Shtirlitz [24]4 years ago
5 0

Answer:

31

Step-by-step explanation:

Take the highest number (75) and subtract the lowest number (44) and you get 31

victus00 [196]4 years ago
4 0

Answer:

Oh that data set okay okay

Step-by-step explanation:

um okay so the first thing you need to do is measure

then you need to find the pattern which in cubic quadrants it would be add 7 subtract 2 add 2 then repeat

which means the answer is 68

hope this helped

and to celebrate do the renegade

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Find the positive difference between the two solutions to the equation <img src="https://tex.z-dn.net/?f=%20%5Cdisplaystyle%5Csq
Verizon [17]

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4 years ago
What is the correct percent of a quiz score of 26 points out of 60
Solnce55 [7]
You just divide 26 by 60 and you get .4333 repeating. To make the decimal a percent you just move the decimal place two places to the right and get about 43%.
5 0
3 years ago
Read 2 more answers
The length of a rectangle is 4 m longer than its width. if the perimeter of the rectangle is 36 m , find its area.
ycow [4]
Answer:   The area of the rectangle is:  " 77 m² " .

__________________________________________________________
Note:  The formula for the area, "A" of a rectangle:

 →  A  =  L  *  w   ;

                 in which:  
     A = "area (of rectangle)" ; [in units of "m² " ; that is:  "square meters" ] ; 
                                     
     L = length = "(4 + w)" {in units of "meters (m)" } ;  
             
     w = width  {in units of "meters (m)" } ; 
_______________________________________________________

So;  " A = L * w " ;  

Substitute the known expression for the "length, L" ;  & rewrite the formula for the given area of OUR area for the rectangle in OUR GIVEN PROBLEM:

              →  A = (4 + w) * w '' ;
______________________________________________________

Note the formula for the perimeter, "P" ; 

 →  P = 2L + 2w  ; 

↔   2L + 2w = P 

 →  2L + 2w  = 36 m ;
_____________________________________________________
We want to find the "area" , "A" :
_____________________________________________________
Using the formula for the "perimeter, "P" (of the rectangle) ; & given that the perimeter is:  "36" (meters) ;  

 →  2L + 2w  = 36 ;

 →  Let us plug in the values for "Length (L)" & "width (w)" ; 

 →  2(w + 4)  + 2w = 36  ; 

So;   (2*w) + (2*4) + 2w = 36 ;  Solve for "w" ;

    →  2w + 8 + 2w = 36 ; 

    → Combine the "like terms" :

         + 2w + 2w = 4w ; 

   →  And rewrite: 

         4w + 8 = 36 ; 

Now, subtract "8" from EACH SIDE of the equation:

         4w + 8 − 8 = 36 <span>− 8 ; 
</span>
to get: 

         4w = 28 ; 

Now, divide EACH SIDE of the equation by "4" ; 
      to isolate "w" on EACH SIDE of the equation ; & to solve for "w" ; 

         4w / 4 = 28 / 4  ; 

           → w = 7 ;   → The "width" of the rectangle is:  " 7 m " .

Now, we can find the "length" of the rectangle:

The length, "L" , of the rectangle = 4 + w = 4 + 7 = 11 .
      
           →  L = 11 .  →  The "length" of the rectangle is:  " 11 m " .
___________________________________________________
 
Now, we can find the area, "A", of the rectangle.

 A = L * w  =  11 m * 7 m  =  " 77 m² " .

  →  The area of the rectangle is:  " 77 m² <span>" .
</span>__________________________________________________

To check our answer:
__________________________________________________
 
→  " P = 2L + 2w "  ; 

Given that "P = 36 m" ; 

Plug in "36 m" (for "P") ; into the equation ;

and plug in our calculated values for
                        "length, L" (which is "11 m") ; & "width, w" (which is "7 m") ; 

to see if the equation holds true ; that is, to see if both sides of the equation are equal ;
_______________________________________________________  

 →  36 m = ?  2L + 2w ?? ;

 →  36 m = ?  2(11 m) + 2(7 m) ?? ; 

 →  36 m = ?  22 m + 14 m ?? ; 

 →  36 m = ?  36 m ?  Yes! 
__________________________________________________
3 0
3 years ago
44 + 45 + 46 + 47 ... + 142 + 143
stealth61 [152]

Answer: 467

If you need anything else let me know I'll galdly help you!

This there was more to the problem then message me and ill redo it.

6 0
3 years ago
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