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2 years ago

15

On a coordinate plane, Point J is plot at (-4,6) and Point K is plotted at (8,-3). What is the distance, in units, between point

s J and K?

1 answer:

zhuklara [117]2 years ago

4 0

Idk I tried this but I can't get it

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5x+6y=18and 18x-15y=36<br> parallel or perpendicular

Katen [24]

Answer:

<u>They</u><u> </u><u>are</u><u> </u><u>neither</u><u> </u><u>parallel</u><u> </u><u>nor</u><u> </u><u>perpendicular</u><u>,</u><u> </u><u>since</u><u> </u><u>slope</u><u> </u><u>are</u><u> </u><u>different</u><u> </u><u>and</u><u> </u><u>not</u><u> </u><u>related</u><u> </u><u>by</u><u> </u><u>any</u><u> </u><u>equation</u>

Step-by-step explanation:

First arrange them according to general equation:

$y = mx + c$

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>f</u><u>i</u><u>r</u><u>s</u><u>t</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

$5x + 6y = 18 \\ 6y = - 5x + 18 \\ { \boxed{y = - \frac{5}{6} x + 3}}$

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

$18x - 15y = 36 \\ 15y = 18x - 36 \\ y = \frac{18}{15} x - \frac{12}{5}$

8 0

2 years ago

Find the product -mnp(3m-5n+7p)

allochka39001 [22]

(−m)(n)p(3m−5n+7p)

=((−m)(n)p)(3m+−5n+7p)

=((−m)(n)p)(3m)+((−m)(n)p)(−5n)+((−m)(n)p)(7p)

=−3m^2np+5mn^2p−7mnp^2

5 0

2 years ago

Of the 400 employees, 5% of them are park managers. How many managers does the park employe

Anvisha [2.4K]

Answer:

The park employed 20 managers.

Step-by-step explanation:

5% of 400

(5 ÷ 100) × 400

0.05 × 400

= 20

8 0

3 years ago

Read 2 more answers

Geometry<br> Solve for x. Round to the nearest tenth of a degree, if necessary.

zvonat [6]

Answer:

13. x = 52.8°

14. 663.65 ft

15. 30.7 ft

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relations between sides of a right triangle and trig functions of the acute angles.

__

<h3>13.</h3>

The sides adjacent and opposite the angle are marked. The relevant trig relation is ...

Tan = Opposite/Adjacent

tan(x°) = 2.5/1.9

The angle is found using the inverse tangent function:

x° = arctan(2.5/1.9) ≈ 52.8°

__

<h3>14.</h3>

Again, the tangent relation comes into play. The given values are the side opposite and the angle, and we are asked for the side adjacent.

Tan = Opposite/Adjacent

tan(11°) = (129 ft)/(distance to shore)

distance to shore = (129 ft)/tan(11°)

distance to shore ≈ 663.65 ft

__

<h3>15.</h3>

In this scenario, the given angle is opposite the given side of the triangle. The measure of the hypotenuse is needed.

Sin = Opposite/Hypotenuse

sin(71°) = (29 ft)/(ladder length) . . . . substitute given information

ladder length = (29 ft)/sin(71°) . . . . . . solve for ladder length

ladder length ≈ 30.7 ft

3 0

1 year ago

Please help me ASAP Please

Romashka [77]

Answer:

I think it’s 20 or 26 sorry if I get it worng :(

5 0

2 years ago