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poizon [28]
3 years ago
15

On a coordinate plane, Point J is plot at (-4,6) and Point K is plotted at (8,-3). What is the distance, in units, between point

s J and K?

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0
Idk I tried this but I can't get it

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Factor the equation <br> please help
LiRa [457]

Answer:

<u>For</u><u> </u><u>A</u>

{ \rm{6 {x}^{2}(x + 1) - 2x(x + 1) }}

• The equation above has a common bracket "(x + 1)". So, let's first factorise out that bracket:

\dashrightarrow \: { \rm{(x + 1) \{6 {x}^{2} - 2x \} }}

• now in the second bracket, the common factor is x and 2.

\dashrightarrow \: { \rm{(x + 1) \{2x(3x - 1) \}}}

• Final answer;

{ \boxed{ \boxed{ \rm{ \dashrightarrow \: 2x(x + 1)(3x - 1) \:  \: }}}}

<u>For</u><u> </u><u>B</u>

{  \rm{3(x - 1)(x + 2) + ( {x}^{2} - x)(x + 2) }}

• In the equation, the common bracket is (x + 2).

So let's first factorise it out:

\dashrightarrow \: { \rm{(x + 2) \{3(x - 1) + ( {x}^{2}  - x) \}}} \\  \\ { \rm{(x + 2) \{3(x - 1) + x(x - 1) \}}}

• In the second major bracket, the common bracket is (x - 1). so factorise it out:

{  \rm{(x + 2) (x - 1) \{3 + x \}}}

• Final answer:

{ \boxed{ \boxed{ \rm{ \dashrightarrow \: (x + 2)(x  + 3)(x - 1) \:  \: }}}}

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What is the integral of 2x?
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Integral of 2x is :

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Look at it this way:
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Gnoma [55]

Answer:

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Step-by-step explanation:

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Is 10 pounds greater or 10 kilograms
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Pounds  is more if you do the math
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