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Alika [10]
3 years ago
9

ALGEBRA 2 PLEASE HELP!!!

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0
1/((R2+R1)/(R2*R1))
= 1/(R2+R1) * (R2*R1)/1
So answer 4
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A store had 175 cell phones in the month of January. Every month, 10% of the cell phones were sold and 10 new cell phones were s
Elenna [48]

Answer: f(n) = 0.9 × f(n − 1) + 10,   f(0) = 175,  n > 0


Step-by-step explanation:

Given: A store had 175 cell phones in the month of January.

Every month, 10% of the cell phones were sold and 10 new cell phones were stocked in the store.

Let n be the number of months

Then when n=0

f(0)=175

After first month , n=1

The number of cell phone in store=175-10\%\ of\ 175+10

Thus f(1)=f(0)-10\%\ of\ f(0)+10

=f(0)-0.1\timesf(0)+10\\=f(0)(1-0.1)+10\\=f(0)(0.9)+10\\

Similarly we can do till n months, we get

f(n)=0.9×f(n−1)+10, f(0) = 175, n > 0

6 0
3 years ago
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7nadin3 [17]
Commutative property
Changing the order doesn’t change the result
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6 0
3 years ago
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Please help me!!!!! Show your work 45-45-90 method <3
aivan3 [116]

Answer:

hope it helps and u understand

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3 years ago
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The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
Lunna [17]

Answer:

x = 2010

Step-by-step explanation:

It is difficult separating and organizing the data.  The best I can see is that the question is asking what is the value of x to make f(x) = t(x) true.  x = 2010  is a year in which enrollment was the same, 740, in both f and t.

3 0
2 years ago
The diameter of a cylindrical construction pipe is 4ft If the pipe is 17ft long, what is its volume? Use the value 3.14 for /pi,
zvonat [6]

Answer:

214 ft^3

Step-by-step explanation:

Here, we are asked to calculate the volume of the cylindrical construction pipe.

Mathematically, the volume V

V = pi * r^2 * h

r is radius = diameter/2 = 4/2 = 2 ft

h = 17ft

pi = 3.14

Putting these values, we have;

V = 3.14 * 2^2 * 17 = 213.52 which is 214 ft^3 to the nearest whole number

8 0
3 years ago
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