Answer:
Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)
Step-by-step explanation:
This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.
First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.
Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.
I personally don’t know the answer so i can’t help
Answer:
#4 vertex form
and
vertex (h,k)
Step-by-step explanation:
vertex form
-2(x-3)^2+32
vertex
(h,k)
(3,32)
and 
both have a common denominator, so you can combine them into a single fraction:
You cannot simplify this fraction further:
- - - - - - - - - - - - - - - - - - - -
Answer:
- - - - - - - - - - - - - - - - - - - - -
Answer:
-12
Step-by-step explanation:
if a=-2 and b=-5
(18-(-2×-5))+4(-5)
(18-(10))-20
8-20
-12
just gotta plug in the given into the equation
