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choli [55]
3 years ago
14

BRAINLIEST + POINTS

Mathematics
1 answer:
Alla [95]3 years ago
5 0

Answer:

(x-2)^2 + (y-4)^2 = 5^2

Step-by-step explanation:

Hello!

The standard equation of a circle with center at (h,k) and radius r is:

(x+h)^2 + (y-k)^2 = r^2.  

Filling in the known info (h=2, k=4, r =5), we get:

(x-2)^2 + (y-4)^2 = 5^2

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Layla reads 2/5 of her book on Saturday and the other 90 pages to finish the book on Sunday how many pages does Layla's book hav
PolarNik [594]
3/5=90
1/5=30
30x5=150
laylas book has 150 pages
5 0
3 years ago
10) Solve using any method<br> 10x+2y=42<br> 5x+y=20
KIM [24]

Answer:

no solutions

Step-by-step explanation:

10x+2y=42

5x+y=20

Multiply the second equation by -2 to use elimination

-2(5x+y)=20*-2

-10x -2y = -40

Add this to the first equation

10x+2y=42

-10x -2y = -40

--------------------------

0 = 2

This is never true.  This means there are no solutions

3 0
3 years ago
Read 2 more answers
3.74 to the nearest thousandth
Y_Kistochka [10]
<span>3.7 since the digit after the tenths digit is less than five</span>
7 0
3 years ago
1) 1.32x10^4 ÷ 2.64×10^3
m_a_m_a [10]
5.) Pluto, Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, Jupiter.
I don't know 1,2,3 and 4.
4 0
3 years ago
The proof that AMNS AQNS is shown.
FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

∠NMS=∠NQS     (∵ MNQ is isosceles triangle)

MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

3 0
3 years ago
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