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3 years ago

6

The average mass of a giraffe is approximately 1 × 10^3 kilograms. The average mass of a blue whale is approximately 2 × 10^6 ki

lograms. About how many times more mass does a blue whale have than a giraffe?

1 answer:

Jlenok [28]3 years ago

7 0

Giraffe = 1,000 kg
Whale = 2,000,000 kg

Whale has 2,000 times the mass.

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Points X and Z are on a number line, and point Y partitions

abruzzese [7]

Answer:

The coordinate of $Z$ is 13.36.

Step-by-step explanation:

According to the statement, we have the following information:

$\frac{XY}{XZ} = \frac{5}{12}$ (1)

$\frac{YZ}{XZ} = \frac{7}{12}$ (2)

$X = 0.4$ (3)

$Y = 5.8$ (4)

From (2), we have the following expression:

$YZ = \frac{7}{12}\cdot XZ$

$Y-Z =\frac{7}{12}\cdot (X-Z)$

$Y - Z = \frac{7}{12}\cdot X -\frac{7}{12}\cdot Z$

$Y-\frac{7}{12}\cdot X = Z-\frac{7}{12}\cdot Z$

$\frac{5}{12}\cdot Z = Y-\frac{7}{12}\cdot X$

$5\cdot Z = 12\cdot Y-7\cdot X$

$Z = \frac{12}{5}\cdot Y-\frac{7}{5}\cdot X$ (5)

If we know that $Y = 5.8$ and $X = 0.4$ , then the coordinate of $Z$ is:

$Z = \frac{12}{5}\cdot (5.8)-\frac{7}{5}\cdot (0.4)$

$Z = 13.36$

The coordinate of $Z$ is 13.36.

6 0

3 years ago

Which point would be a solution to the system of linear inequalities ?

brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

$y\leq \frac{4}{3}x+5$ ----> inequality A

$y\geq -\frac{5}{2}x+5$ ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

$-1\leq \frac{4}{3}(0)+5$

$-1\leq5$ ----> is true

Inequality B

$-1\geq -\frac{5}{2}(0)+5$

$-1\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

$3\leq \frac{4}{3}(0)+5$

$3\leq5$ ----> is true

Inequality B

$3\geq -\frac{5}{2}(0)+5$

$3\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

$-6\leq \frac{4}{3}(-6)+5$

$-6\leq-3$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(-6)+5$

$-6\geq 20$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

$-6\leq \frac{4}{3}(12)+5$

$-6\leq21$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(12)+5$

$-6\geq -25$ ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

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3 years ago

An automobile manufacturer has given its van a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Fynjy0 [20]

Answer:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

Step-by-step explanation:

Information given

$\bar X=31.1$ represent the sample mean

$\sigma=1.3$ represent the population standard deviation

$n=140$ sample size

$\mu_o =31.3$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:

Null hypothesis: $\mu =31.3$

Alternative hypothesis: $\mu \neq 31.3$

Since we know the population deviation, the statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

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3 years ago

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svetoff [14.1K]

You have to find the area of each face and add them all together. You also need to find the unknown side which is indicated in the picture i attached.

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paige and her family went tp the movies. they bought 4 tickets and paid $12 for popcorn. they spent $40. how much did each ticke

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Hello!

First of all, we subtract the popcorn cost, 12, from 40, giving us 32. Now we divide by 4 tickets.

32/4=8

Therefore, each ticket costed $8.

I hope this helps!

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