F(x) = 2(x - 3)^2 - 2

Mathematics

1 answer:

Natali5045456 [20]3 years ago

4 0

Hi. I was unsure of what exactly you wanted from this equation, so here's a quick analysis:

f(x) = 2(x - 3)^2 - 2

Domain: (-∞, ∞)

Range: (-2, ∞)

X-intercepts: (4, 0), (2, 0)

Y-intercept: (0, 16)

Axis of Symmetry: x = 3

Minimum value (vertex): (3, -2)

Standard form: y = 2x^2 - 12x + 16

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