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3 years ago

10 gallons equal how many cups

Mathematics

2 answers:

Gnesinka [82]3 years ago

4 0

160 cups are in an gallon :) good luck!!

leonid [27]3 years ago

3 0

If one gallon equals to 16 cups, then 16 * 10 will be your answer.

10 * 16 = 160

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a tree was 62 inches tall. Three years later, it was 101 inches tall. What was the percent increase, to the nearest hundredth, o

nignag [31]

Answer:

63% increase.

Step-by-step explanation:

You don't really need to do anything because it's probably a 63% increase as 101 is close to 100 already. If you'd like:

$\frac{101-62}{62} *100=$

$\frac{39}{62} *100=$

$62.903225806451612903225806451613$ ≈

63%

8 0

3 years ago

What is number 5???!!

vagabundo [1.1K]

The value of m∠M is 112°

Step-by-step explanation:

In the parallelogram NPMQ, opposite angles ∠P=∠M.

To get the value of the angles, equate the two expressions;

(6x-2)°=(4x+36)°

6x-2=4x+36 ------ collect like terms

6x-4x=36+2

2x=38

x=38/2 =19

So, ∠M= (6x-2)° = (6×19 - 2)° = 112°

Learn More

Angles in a parallelogram : brainly.com/question/11611093

Keyword : angles

#LearnwithBrainly

8 0

3 years ago

Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$