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4 years ago

Chooose the like terms 3h,i,4i answer

1 answer:

8 0

I and 4i
let's say if you have i you can automatically think there is a one in front of it so one term like this (i) could look like this 1i and any number with the same variable or letter are like terms
hope this helps

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Really really need help on ONE math graph question.

Nat2105 [25]

The answer is -3.5, 0.5

7 0

3 years ago

Given that Ray B A bisects ∠DBC, which statement must be true? m∠ABD = m∠ABC AB ≅ BC B is the midpoint of DC. m∠DBC = 90°

nadya68 [22]

Answer:

A. $m\angle ABD=m\angle ABC$

Step-by-step explanation:

We are given that a ray BA bisects angle DBC.

We have to find true statement .

Angle bisector property:When a ray bisect any angle then the angles made by bisection of angle are equal.

When ray BA bisects angle DBC

Then, $m\angle ABD=m\angle ABC$

By angle bisector property.

Therefore, option A is true.

Answer:A. $m\angle ABD=m\angle ABC$

4 0

3 years ago

Read 2 more answers

PLEASE HELP IM SO CONFUSED!!!

Step2247 [10]

Problem 1

The median weight of the Welsh corgis is 27 pounds. This is found in the table in row 1, column 2. Recall that the median is the middle most value, so that means 50% of the Welsh corgi weights will be less than 27 pounds, and also 50% of the weights are greater than 27 pounds.

========================================================

Problem 2

The Welsh corgis have the greater variation in weights. Why is this? There are two pieces of evidence:

The first of which is that the range for the first row (7) is larger than the range in the second row (2). The range is the difference between the max and min. The larger the range, the more spread out the data set will be.

The second piece of evidence is that the MAD (mean absolute deviation) for the Welsh corgis is larger compared to the MAD for the cocker spaniels group. The MAD is another way to measure the spread of a data set. Like the range, the larger the MAD gets, the more spread out the data is. It measures how far on average any given value is from the mean. It's similar to the standard deviation and variance, which are also measures of spread.

========================================================

Problem 3

Both dog breeds have the same mean value, and roughly the same median. Both the mean and median are measures of center. Based on just these two pieces of info alone, we could easily conclude that both dog groups have the same distribution more or less. Furthermore, we could conclude that both groups have roughly the same max weight value.

However, we discussed in problem 2 that the first group (Welsh corgi) is more spread out, so it's likely that could heavily imply that the min and max values are further from the center compared to the second group of dogs. Having a larger max would then mean that the corgi group has the largest weight.

In short, the answer is "Welsh corgi" due to this group having a greater spread, and that pushes the max further away from the center.

7 0

3 years ago

Read 2 more answers

A zoo has 60 penguins total if the emperor penguins make up 35% of all the penguins at the zoo how many emperor penguins are at

Kruka [31]

Answer:

21 emperor penguins

Step-by-step explanation:

1. Convert 35% to decimal form

0.35

2. Multiply 0.35 by 60

3. The answer is 21

4 0

3 years ago

Melanie is looking for a loan. She is willing to pay no more than an effective rate of 9.955% annually. Which, if any, of the fo

lakkis [162]

Answer:

c) A and B, being r(loan a)= 9.699% annually, r(loan b)=9.862% annual

Step-by-step explanation:

Hi, well, let´s transform all this nominal rates into effective annual rates.

Loan A: 9.265% nominal rate, compounded weekly

In order to find the easiest effective rate, we need to divide this rate by 52 (which are the weeks in a year). Once we do that, we convert this effective weekly rate into an effective annual rate. Let´s walk you through all this.

$r(E.week)=\frac{0.09265}{52} =0.00178173$

Or 0.178173% effective weekly. Now we can transform it into an effective annual rate.

$r(e.a)=(1+r(e.week))^{52} -1$

$r(e.a)=(1+0.00178173)^{52} -1=0.09699$

Or 9.669% annual, which is less than 9.955%, so this one is sellected, let´s check the next.

Loan B: 9.442% nominal rate, compounded monthly

Just like we did with Loan A, we need to divide this rate too, only this time, we will divide by 12, therefore obtaining an effective monthly rate.

$r(E.month)=\frac{0.09442}{12} =0.00786833$

Or 0.786833% effective monthly, let´s turn it into a effective annual rate.

$r(e.a)=(1+r(e.month))^{12} -1$

$r(e.a)=(1+0.00786833)^{12} -1=0.09862$

Or 9.862% annual, so this rate would work for Melanie too. This means that option C) is the answer we are looking for but, let´s walk that extra mile and turn that Loan C rate into an annual rate.

$r(E.quarter)=\frac{0.09719}{4}=0.0242975$

or 2.42975% effective quarterly, now, let´s convert it into an effective annual rate.

$r(e.a)=(1+0.0242975)^{12} -1=0.10079$

That is 10.079% effective annual, therefore, Loan C is not an option for Melanie.

Best of Luck.

5 0

3 years ago

Read 2 more answers