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nataly862011 [7]
3 years ago
11

Which equation represents a like that passes through (4,1/3) and has a slope of 3/4?

Mathematics
1 answer:
elixir [45]3 years ago
7 0
The slope intercept form is y = mx + b
you need to find the equation that has a slope of 3/4 and passes through (4,1/3)

Plug in the given into the equation
y = 3/4x + b
to solve for the y-intercept, plug in the given coordinate that the line passes through

1/3 = 3/4(4) + b
1/3 = 3 + b
subtract 3 from both sides 
-8/3 = b

now back to the slope intercept equation
y = mx + b
plug in the slope and y-intercept
y = 3/4x - 2 2/3
or 
y = 3/4x - 8/3


Hope this helps :)
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nadezda [96]

Answer:

d = \sqrt[2]{34}

Step-by-step explanation:

We are solving for the segment of AB. Note that it is a line segment, so there will be end points, those being A(-4, 5) & B(2, -5).

Use the following distance formula:

<em />distance<em> </em>(d) = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - x_{2})^2 }

Let:

Point B(2 , -5) = (x₁ , y₁)

Point A(-4 , 5) = (x₂ , y₂)

Plug in the corresponding numbers to the corresponding variables.

d = \sqrt{(-4 - 2)^{2} + (5 - (-5))^{2} }

Simplify. Remember to follow PEMDAS. First, solve the parenthesis, then the powers, then add, and then finally square root.

d = \sqrt{(-6)^{2} + (5 + 5)^{2}  } \\d = \sqrt{(-6 * -6) + (10)^2} \\d = \sqrt{(36) + (10 * 10)} \\d = \sqrt{36 + (100)} \\d = \sqrt{136}

Simplify:

d = \sqrt{136} = \sqrt{2 * 2 * 2 * 17}  = \sqrt[2]{17 * 2} = \sqrt[2]{34}

d = \sqrt[2]{34} is your answer.

~

3 0
4 years ago
Calculate the first difference between 7, and where 7,-688. 2​
Nataly_w [17]

The difference between the numbers given is 6.882.

<h3>How to illustrate the information?</h3>

Based on the information given, it should be noted that difference means subtraction.

The difference between the numbers given will be:

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= 7 - 0.118

= 6.882

Learn more about difference on:

brainly.com/question/148825

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Answer:

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