2 years ago

a circular mirror has a diameter of 22 inches which measurement is closest to the area of the mirror in square inches

Mathematics

1 answer:

Verdich [7]2 years ago

7 0

Answer:

379.94 square inches

Step-by-step explanation:

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G use part 1 of the fundamental theorem of calculus to find the derivative of the function. sqrt(4+7t)

uysha [10]

Let y = √4+7t
then u= 4+7t
y=√u = u^½

du/dt= 7
dy/du = ½U^-½

dy/dt = du/dt • dy/du
= 7×½U^-½
= 7/2√U
= 7 / (2{√4+7t})

6 0

2 years ago

Okay so I’m stuck on 5.<br> It says “ 10% of __ is 7” what’s the __ answer?

Marat540 [252]

10% of 70 is 7
.1 times 70 is 7
so the answer should be 70

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2 years ago

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If x= –4 and y= 3 , what is the value of x–3y2 ?

Tpy6a [65]

Answer:

-31

Step-by-step explanation:

(-4)-3(3)^2

-4-3(9)

-4-27=-31

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3 years ago

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4a (8a- 4a + 1)<br> Helpehelpeekendnhdhdjdjdjjdfjjfjfjf

Triss [41]

Complete the math in the brackets (4a + 1)

Multiple each term in the brackets by 4a

4a (8a - 4a + 1)
4a (4a + 1)
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2 years ago

Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14

Mumz [18]

Answer:

$Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

Step-by-step explanation:

The equation of the curve is

$Y = sin^{-1}(7x)$

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

$Y'=\frac{7}{\sqrt{1-49x^2} }$

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is $x = \sqrt{\frac{1}{7} }$

Then slope would accordingly be

$Y'=\frac{7}{\sqrt{1-49/49} }$

= ∞

For, $x = \sqrt{\frac{1}{7} }$ , $Y = sin^{-1}(7/7)= \pi/2$

Equation of tangent line, in the point slope form, would be $Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

4 0

2 years ago