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GarryVolchara [31]
2 years ago
5

Derek had 20 trophies and 1/4 of them were golf trophies. How many trophies were not for golf?​

Mathematics
1 answer:
vivado [14]2 years ago
5 0
1/4 of 20 is 5
so there were 5 golf trophies
20-5=15
15 were not golf
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–125 ÷ –5 = ? A. –23 B. –25 C. 23 D. 25
vovikov84 [41]

Answer:

The answer is 25

Step-by-step explanation:

6 0
3 years ago
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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

3 0
3 years ago
Read 2 more answers
A warehouse is 55 yards long, 35 yards wide, and 5 yards high. What is the area of the warehouse floor? If the warehouse is fill
amid [387]

Answer:

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

Step-by-step explanation:

First we have to calculate the area, for this we must multiply the length by the width

a = area

l = long = 55yd

w = width = 35yd

a = l * w

a = 55yd * 35yd

a = 1925yd²

to calculate the volume we have to multiply the area by the height

asks us for the volume for half the height so we have to divide the height by 2

a = area = 1925yd²

h = height = 5yd/2 = 2.5yd

v = volume

v = a * h

v = 1925yd² * 2.5yd

v = 4812.5yd³

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

5 0
3 years ago
What is x^2=7x <br><br> number 9
ipn [44]

Let's do this in steps, show your work!

<u>#1. We need to move all terms to one side.</u>

<u>x^2 - 7x = 0</u>

<u>#2. Then factor out the common term x.</u>

<u>x(x - 7) = 0.</u>

<u>#3. Simplify to get..</u>

<u>x = 0, 7.</u>

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8 0
3 years ago
10. Given Triangle GHI with G(7, 0), H (-5, 5) and I (1, 9), find the slope of HI.
Y_Kistochka [10]
H = (-5,5)
I = (1,9)

slope formula : (y2 - y1) / (x2 - x1)
slope = (9 - 5) / (1 - (-5) = 4 / (1 + 5) = 4/6 reduces to 2/3 <==
3 0
3 years ago
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