Answer:
441
Step-by-step explanation:
Answer:
16+2=18
18-3=15
2*3=6
Step-by-step explanation:
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Technician __Shutdown
Taylor, T___4
Rousche, R _ 3
Hurley, H__ 3
Huang, Hu___2
Gupta, ___ 5
The Numbe of samples of 2 possible from the 5 technicians :
We use combination :
nCr = n! ÷ (n-r)!r!
5C2 = 5!(3!)2!
5C2 = (5*4)/2 = 10
POSSIBLE COMBINATIONS :
TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG
Sample means :
TR = (4+3)/2 = 3.5
TH = (4+3)/2 = 3.5
THu = (4+2) = 6/2 = 3
TG = (4 + 5) = 9/2 = 4.5
RH = (3+3) = 6/2 = 3
RHu = (3+2) /2 = 2.5
RG = (3 + 5) = 8/2 = 4
HHu = (3+2) = 2.5
HG = (3+5) = 8/2 = 4
HuG = (2+5) / 2 = 3.5
Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4
Population mean :
(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4
Population Mean and mean of sample means are the same.
This distribution should be approximately normal.
Answer:
26
Step-by-step explanation:
5x+6y
substitute x=16 and y=-9:
5*16+6*(-9)
=80-54
=26
Answer:
27 and 23
Step-by-step explanation:
We can solve this problem as a system of equations. X is the first number and Y is the second number.
The first equation is x+y = 50 and the second equation is x-y=4
Now we solve the system, using elimination method:
x+y=50
x-y=4
2x = 54
x = 54/2
x = 27
And from any of the equations we can find Y
27 + y = 50
y = 50 - 27
y = 23
