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2 years ago

10

What’s the length of a box with a volume of 720 cubic inches, a width of 15 inches, and a height of 4 inches? (Hint: Isolate the

length (L) on one side of the formula V = LWH.)

1 answer:

Tom [10]2 years ago

4 0

Box volume = height * width * length. In this problem we want the length, so we solve the given equation for length:

720 in^3

length = -------------------- = 12 in

(15 in)(4 in)

The box is 12 inches long.

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When factored completely, which is a factor of 3x3 − 9x2 − 12x?

Annette [7]

Answer: I believe it’s D

Step-by-step explanation:

4 0

2 years ago

Part I: Marco rented a small moving van. The moving company charges $40 a day for up to 5 days. The input is the time, in days,

irina1246 [14]

Answer:

(a) It is a function.

(b) D = [1,2,3,4,5]

(c) R = [40,80,120,160,200]

Step-by-step explanation:

(a) Is this a function?

Yes, in order to be a function we need two groups, in this case "time in days" and "total cost". From this group the first one is called the domain, while the other one is called range. The elements in the domain can only have one associated element in the range. By this definition the graph displays a function.

(b) What is the domain?

The domain of a function are the numbers which represent the possible input. In this case it is the group of integer numbers from 1 to 5, in order words D = [1, 2, 3, 4, 5].

c) What is the range?

The range is the group which represent the output of the function and in this case it is the group R = [40, 80, 120, 160, 200]

8 0

3 years ago

A theater club sold 540 tickets . On the first day, 55% of the 40 tickets were sold. how many tickets were sold on the first day

solong [7]

A lot maybe more!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

5 0

3 years ago

Read 2 more answers

To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne

Naily [24]

Answer:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

$\hat p=\frac{67}{150}=0.447$ estimated proportion of applicants who request financial aid

$p_o=0.35$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

5 0

3 years ago

What are the maximum and minimum of the function f(x) = 0.9 I -(x - 5) I + 7 ? A. Maximum at (5,7) and minimum at (0,0) B. Minim

user100 [1]

Answer:

$Minimum = (5,7)$

No maximum

Step-by-step explanation:

Given

$f(x) = 0.9|-(x - 5)| + 7$

Solving (a): The minimum

The minimum is when the absolute parameter gives 0

i.e.

$0.9|-(x - 5)| =0$

Divide both sides by 0.9

$|-(x - 5)| =0$

Open bracket

$|-x + 5| =0$

Remove absolute sign

$-x + 5 =0$

Collect like terms

$x = 5$

Then the y value is:

$f(x) = 0.9|-(x - 5)| + 7$

Recall that: $0.9|-(x - 5)| =0$

So, we have:

$f(x) = 0 + 7$

$f(x) = 7$

Hence, the minimum is at: $(5,7)$

Since the minimum is at $(5,7)$ , then the graph will open upwards.

Hence. the function has no maximum; i.e.

$Maximum = (\infty,\infty)$

7 0

3 years ago