Doug is 5 years old.
5 + 3 = 8
5 × 8 = 40
We are given: On january 1, 2000 initial population = 67,255.
Number of people increase each year = 2935 people.
Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.
Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).
So, we can setup an equation as
Total population after t years = Number of t years * rate of increase of population + fix given population.
In terms of function it can be written as
P(t) = t * 2935 + 67255.
Therefore, final function would be
P(t) = 2935t +67255.
So, the correct option is d.P(t) = 67255 + 2935t.
Answer:
Step-by-step explanation:
Just Square the numbers like a normal equation.
4² = 16
9² = 81
This gives us
or 0.198 as a decimal (approx)
H is the correct answer. Y= (x+2)^2-5
2 to the left x+2=0 x=-2
5 dpwn
You would distribute then combine like terms to get your answer.
