All categories

4 years ago

Can someone help yo girl out, and help me graph this?

Mathematics

2 answers:

LekaFEV [45]4 years ago

8 0

Answer:

Step-by-step explanation:

Darya [45]4 years ago

6 0

the y axis isthe top and bottom the x is horizantal

You might be interested in

A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on three numbers pays 11 to 1 (that is, if you bet $1 and one of

OLga [1]

Answer:

You are expected to lose $0.05 (or win -$0.05)

Step-by-step explanation:

Since the roulette wheel has the numbers 1 through 36, 0, and 00, there are 38 possible outcomes.

In this bet, you are allowed to pick 3 out of the 38 numbers. Thus, your chances of winning (P(W)) and losing (P(L)) are:

$P(W)=\frac{3}{38}\\P(L) = 1 - P(W)\\P(L) = \frac{35}{38}\\$

The expected value of the bet is given by the sum of the product of each outcome pay by its probability. Winning the bet means winning $11 while losing the bet means losing $1. The expected value is:

$EV = (11*\frac{3}{38}) -(1*\frac{35}{38})\\EV = -\$0.0525$

Therefore, with a $1 bet, you are expected to lose roughly $0.05

5 0

3 years ago

Pat has nine cards. Frank has two more cards than Steve. Steve has 3 cards how many more cards does Pat have than Frank?

n200080 [17]

4. Pat 9. Frank 5. Steve 3. 9-5=4.

4 0

4 years ago

Read 2 more answers

How did the transformation of ()=f of , open x close . equals , x squared to ()=−g of , open x close . equals , x squared , minu

Nikolay [14]

The intercepts are the points where the graph crosses the x or y-axis

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3

The functions are given as:

$f(x) = x^2$

$g(x) = x^2 - 3$

Function f(x)

$f(x) = x^2$

The x-intercept is calculated as follows:

Set f(x) to 0

$x^2 = 0$

Solve for x

$x = 0$

The y-intercept is calculated as follows:

Set x to 0

$f(0) = 0^2$

$f(0) = 0$

Hence, the intercepts are 0

Function g(x)

$g(x) = x^2 - 3$

The x-intercept is calculated as follows:

Set g(x) to 0

$x^2 - 3 = 0$

Solve for x

$x^2 = 3$

$x = \±\sqrt 3$

The y-intercept is calculated as follows:

Set x to 0

$g(x) = x^2 - 3$

$g(0) = 0^2 - 3$

$g(0) = - 3$

The x-intercepts are $\±\sqrt 3$ , while the y-intercept is -3

By comparing the intercepts of f(x) and g(x),

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3