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Vlada [557]
3 years ago
12

given f(x)= 3 square root x-5 , g(x)= x^3+1 find g f(x). Can someone explain to me this question step by step? I don’t know why

I’m getting wrong answer pls help!
Mathematics
1 answer:
Tomtit [17]3 years ago
4 0

f(x) = 3 \sqrt{x - 5}  \\ g(x) =  {x}^{3}  + 1 \\ g(f(x)) = g(3 \sqrt{x - 5} )

rewrite x in g(x)

=  {(3 \sqrt{x - 5}) }^{3}  + 1 \\  =  {3}^{3}  \times  {( \sqrt{x - 5} )}^{3}  + 1  \\ = 27(x - 5) \sqrt{x - 5}  + 1

just observe ?

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