A=g≈-32
v=⌠a dt since a≈-32
v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s
v=-32t+20
h=⌠v dt
h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height? How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P
h=-16t^2+20t+3
Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:
h(t)=-16t^2+20t+hi, where hi is the initial height in feet.
This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)
So for example B(4,1) so x=4, y=1
->B'(4-2,1-4)
->B'(2,-3)
->A'(1-2,1-4)
->A'(-1,-3)
->C'(4-1,-2-4)
->C'(3,-6)
->D'(1-2,-2-4)
->D'(-1,-6)
so the image of the rectangle ABCD->A'B'C'D'
Answer:
There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555
Step-by-step explanation:
Given the functions:
f(x) = x² + 4x + 10
g(x) = -32x - 40
we want to find the points at which f(x) = g(x).
x² + 4x + 10 = -32x - 40
x² + 4x + 10 + 32x + 40 = 0
x² + 36x + 50 = 0
Using quadratic formula:
