Ask question

Ask question

All categories

3 years ago

12

Please help me with this question from my homework: (Answers in English please :) In the figure, m<1=7x+8, m<2=4x+11, and

m<4=12x+7. What is the m<1?
For context m<1 means measure of angle 1

2 answers:

pickupchik [31]3 years ago

5 0

Angle 1 is 54.9 (rounded)

BigorU [14]3 years ago

4 0

Answer:

54.896

Step-by-step explanation:

You might be interested in

I need help now I’m stuck!

trapecia [35]

Whats the question?

6 0

2 years ago

Read 2 more answers

Are the following figures similar?

Tcecarenko [31]

No the corresponding angles are not congruent, because the angle measures on the smaller figure are 90, 90, 137, and 43, while the larger figure has angle measures of 90, 90, 136, 44. that is why the following figures are not congruent.

3 0

3 years ago

4k + 15 greater than -2k + 3

ioda

Answer:

k>-2

Step-by-step explanation:

4k+15>-2k+3

4k-(-2k)+15>3

4k+2k+15>3

6k+15>3

6k>3-15

6k>-12

k>-12/6

k>-2

8 0

3 years ago

CAN SOMEBODY HELP AND DO THIS PLEASEEEEEEEEE

Keith_Richards [23]

Answer:

65

Step-by-step explanation:

180-115=65 bc all the lines are parallel.

7 0

2 years ago

Read 2 more answers

Solve for x in the given interval.<br><br> sec x= -2√3/3, for π/2 ≤x≤π

drek231 [11]

Answer:

b. $x=\frac{5\pi}{6}$

Step-by-step explanation:

The given function is

$\sec x=-\frac{2\sqrt{3} }{3},\:\:for\:\:\frac{\pi}{2}\le x \le \pi$

Recall that the reciprocal of the cosine ratio is the secant ratio.

This implies that;

$\frac{1}{\cos x}=-\frac{2\sqrt{3} }{3}$

$\Rightarrow \cos x=-\frac{3}{2\sqrt{3} }$

$\Rightarrow \cos x=-\frac{\sqrt{3}}{2}$

We take the inverse cosine of both sides to obtain;

$x=\cos^{-1}(-\frac{\sqrt{3}}{2})$

$x=\frac{5\pi}{6}$

4 0

3 years ago